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s2008m [1.1K]
3 years ago
12

What is the average height in feet for students in your class? It is measured in the ______

Mathematics
1 answer:
I am Lyosha [343]3 years ago
5 0
Definitely the ones (A). Since its measured in feet the tallest person should be around 6 feet which does not pass 10.
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A paper cup shaped like a cone has a diameter of 6 centimeters and a slant height of 7.5 centimeters. About how much paper is ne
liq [111]

Answer:

22.5 cm^2

Step-by-step explanation:

Amount of paper is going to be measured in area, so we want the surface area of the cone.  Since it is a cub it doesn't have a base, so we don't need to count it.  

Area of the cone without the base, or what is called the lateral area is pi*r*s where r is the radius and s is the slant height.  and of course radius is d/2 where d is the diameter.  so let's plug it in.  We know diameter is 6 and slant height is 7.5

SA = pi * r * s

SA = pi * d/2 * s

SA = pi * 6/2 * 7.5

SA = 22.5 cm^2

So you will need 22.5 square centimeters of paper.

4 0
2 years ago
1. Girl Scout Troop 321 started with 25 girls and at the end of the year party there were 31 girls. Gabby
Oksanka [162]

Answer: 24%

Step-by-step explanation:

Since we are informed that the Girl Scout Troop started with 25 girls and at the end of the year party there were 31 girls. The percentage change will be:

= (31 - 25) / 25 × 100

= 6/25 × 100

= 24%

The error that Gabby made was that she used 31 as the base. This is expressed below:

= 31 - 25) / 31 × 100

= 6/31 × 100

= 19.4%

3 0
3 years ago
An airplane flies from New Orleans Atlanta Georgia and an average of the airplane then returns on average rate of 280 mph travel
JulsSmile [24]

Answer:

and ? what is the question

Step-by-step explanation:

5 0
3 years ago
A parallelogram is shown below. Which equation best represents the formula for the area of the parallelogram?
adell [148]

The area of a parallelogram is length x height.

The answer would be C. A = 12 • 8

7 0
3 years ago
What is the answer to K/2+1-1k=-2k
Mazyrski [523]

\dfrac{k}{2}+1-1k=-2k\\\\\dfrac{1}{2}k+1-k=-2k\\\\\left(\dfrac{1}{2}k-k\right)+1=-2k\\\\-\dfrac{1}{2}k+1=-2k\qquad\text{subtract 1 from both sides}\\\\-\dfrac{1}{2}k=-2k-1\qquad\text{add 2k to both sides}\\\\1\dfrac{1}{2}k=-1\qquad\text{convert the mixed number to improper fraction}\\\\\dfrac{1\cdot2+1}{2}k=-1\\\\\dfrac{3}{2}k=-1\qqua\text{multiply both sides by}\ \dfrac{2}{3}\\\\\boxed{k=-\dfrac{2}{3}}

4 0
3 years ago
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