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balu736 [363]
2 years ago
14

Help ! please ! with 13, 14, 15, 16, 17, 18, 19, 20, 21,

Mathematics
1 answer:
sasho [114]2 years ago
3 0

Answer:

0.786

0.3563

0.234

0.9

0.324

0.847

0.34

0.446

0.245

Step-by-step explanation:

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DIscrete Math
Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

  1. f : X \rightarrow Y is surjective implies there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y.
  2. If there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y, then f : X \rightarrow Y is surjective

Let us start by the first implication.

Our hypothesis is that the function f : X \rightarrow Y is surjective. From this we know that for every y\in Y there exist, at least, one x\in X such that y=f(x).

Now, define the sets X_y = \{x\in X: y=f(x)\}. Notice that the set X_y is the pre-image of the element y. Also, from the fact that f is a function we deduce that X_{y_1}\cap X_{y_2}=\emptyset, and because  f the sets X_y are no empty.

From each set X_y  choose only one element x_y, and notice that f(x_y)=y.

So, we can define the function h:Y\rightarrow X as h(y)=x_y. It is no difficult to conclude that f\circ h(y) = f(x_y)=y. With this we have that f\circ h=1_Y, and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function  h:Y\rightarrow X  such that f\circ h=1_Y.

Take an element y\in Y, then f\circ h(y)=y. Now, write x=h(y) and notice that x\in X. Also, with this we have that f(x)=y.

So, for every element y\in Y we have found that an element x\in X (recall that x=h(y)) such that y=f(x), which is equivalent to the fact that f is surjective. Therefore, the prove is complete.

3 0
3 years ago
A miner descended 1400 feet into a mine from the mine's entrance. While in the mine, he then rose 800 feet and then descended 45
postnew [5]
The correct answer is A.-1050
7 0
3 years ago
Read 2 more answers
Find the cosine of angle A to the nearest 100th.
Sauron [17]

Answer:

{ \tt{ \cos(A) =  \frac{ \sqrt{700} }{40}  }} \\  { \tt{ \cos(A) = 0.66 }}

4 0
3 years ago
What is the volume of a right circular cone that has a height of 18.8 m and a base with a radius of 19.3 m
12345 [234]

Answer: 7,333.32 m3

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume of a cone = 1/3 x π x radius^2 x height

Replacing with the values given:

V = 1/3 π (19.3)^2 (18.8) = 7,333.32 m3

The volume of the right circular cone is 7,333.32 cubic meters.

Feel free to ask for more if needed or if you did not understand something.  

7 0
3 years ago
Read 2 more answers
Which of the relations given by the following sets of ordered pairs is a function?
KonstantinChe [14]

9514 1404 393

Answer:

  (a)  {(5, 2), (-4, 2), (3, 6), (0, 4), (-1, 2)}

Step-by-step explanation:

The only relation with no repeated x-values is the first one. The first relation is a function.

6 0
3 years ago
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