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S_A_V [24]
3 years ago
6

A highway engineer specifies that a certain section of roadway covering a horizontal distance of 2km should have a downgrade of

8%. Compute the change in elevation of this section of road. Use the slope formula.
Mathematics
2 answers:
Dafna11 [192]3 years ago
6 0

Answer: ∆h = 0.16km = 160m

The Change in elevation is 0.16km

Step-by-step explanation:

Given:

Change in elevation m= 8% = 0.08

Which means for every 100 units change in horizontal distance there would be 8 units change in elevation.

Horizontal distance of road x= 2km

Using the equation;

∆h = mx

Where ∆h = change in elevation

∆h = 0.08 × 2km

∆h = 0.16km = 160m

Zigmanuir [339]3 years ago
3 0

Answer:

0.16km

Step-by-step explanation:

A highway engineer wants to compute  the change in elevation of a section of road. The horizontal distance of this section of road is 2km and downgrade is 8%

The slope formula is given by

m=\frac{rise}{run}=\frac{x}{y}

m = 8% = 8/100

run = y = 2km

m =\frac{x}{y}

\frac{8}{100} =\frac{x}{2}

\frac{2*8}{100} =x

x=\frac{16}{100} =0.16km

Verification:

m=\frac{0.16}{2}= 0.08=8%%

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6 0
3 years ago
A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr
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Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N      Mass of the man,(m)= \frac{W}{g} = \frac{748}{9.8} = 76.32 kg

Radius of the pond (r) = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is V_m .

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m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)

Considering V_m_(_f_)=V_m

And initial velocity of both the man and book i.e V_b_(_i_)=0,\ V_m_(i_)=0

So,

⇒ 0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m

⇒ Plugging the values.

⇒ V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}

⇒ V_m=-\frac{1.2\times 4}{76.32}

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Here the negative velocity is meant for opposite direction of the throw.

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With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know velocity(v)\times time(t) = distance(d)

Let the time taken be t and v\times t = d and d=r then, V_m\times t=r

Then

⇒ t=\frac{radius\ (r)}{V_m}

⇒ Plugging the values.

⇒ t=\frac{4}{0.062}

⇒ t =64 sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0
3 years ago
A total of 26 bills are in a cash box. Some of the bills are one-dollar bills, and the rest are five-dollar bills. The total amo
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Answer:

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