What are these points someone plz help me
1 answer:
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the coordinates where the bridges must be built is and
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<u>Step-by-step explanation:</u>
Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:
Basically we need to find values of x for which f(x) = g(x) :
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Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6
Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3
Therefore , the coordinates where the bridges must be built is and
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You can use the fact that when mode is used, negative and positive all values become non-negative.
The equation that represents the function graphed on the given coordinate plane is given by
Option B: g(x) = |x+4| -10 is the equation which represents the function graphed on the coordinate plane.
<h3>How to know what function is graphed on the coordinate plane?</h3>We see what points it goes through, what type of nature it is showing where (like for example, the given function firstly goes down straightly, then rise up straightly after x = -4 ). We can see on what value of x, does the function become 0.
Many such graphical analysis help us to analyze which function can represent the given graph.
<h3>How to analyze given graph?</h3>The graph contains straight lines, so it must be linear.
The graph contains a twist in the direction where it was going initially and changes the direction. This shows that the graph is using something else than just a regular linear equation.
The graph turns up after it goes through x = -4.
Let we try to make equation of straight lines before and after x = -4 which the graph follows.
The first line goes 1 block down (1 block is of 2 units) on y axis as we go 1 block left on x axis. Thus the slope will be -2/2 = -1 (we take slope as rise/run and since rise was down thus it is taken as -ve rise).
The slope intercept form of this line would be
Since the line passes through point x = -4, y = -10, thus this point must satisfy the equation of that line since an equation represents the family of points which make up the given line.
Thus,
Thus, the equation of first line would be y = -x -14
The equation of second line, let be y = mx + c.
Since the second line intersects the y axis at y = -6, thus the y intercept of this line is -6 or c = -6.
Since the line rises 1 block( = 2 units) as one block of run happens on x axis in left direction (we take left as positive and right direction run as negative. This is standard sign convention used by most of the mathematical community. Conventions are just to remove ambiguity on international level). Thus, the slope of this line is 2/2 = 1
Thus, m = 1 or the equation of this line would be:
We can rewrite both the lines as:
But the graph has first line till x <= -4 and second line from x >= -4
Thinking carefully on this fact, we can see that when x <= -4 in first line, the -(x+4) is positive or 0
Similarly, for second line, when x >= -4,
the (x+4) is positive or 0
Thus, we can merge both equations using mode:
y = -10 + |x+4|
which will make x+4 to stay positive all the way. Thus, when x <= -4, this will simulate the first line, and when x >= -4, this will simulate the second line.
Note that at x = -4, both the lines have y = -10.
Thus, Option B: g(x) = |x+4| -10 is the equation which represents the function graphed on the coordinate plane.
Learn more about straight line here:
