The tenths place digit is the digit right after the decimal point.
So in 264.5, the tenth digit is 5.
Idk I have tried and failed miserably
Answer:
You should expect to find the middle 98% of most head breadths between 3.34 in and 8.46 in.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
In what range would you expect to find the middle 98% of most head breadths?
From the: 50 - (98/2) = 1st percentile.
To the: 50 + (98/2) = 99th percentile.
1st percentile:
X when Z has a pvalue of 0.01. So X when Z = -2.327.
99th percentile:
X when Z has a pvalue of 0.99. So X when Z = 2.327.
You should expect to find the middle 98% of most head breadths between 3.34 in and 8.46 in.
We can sum two fractions if they have the same denominator, so we have to rewrite both fractions so that they'll have the same denominator.
We can generate equivalent fractions by multiplying both numerator and denominator by the same number.
So, we have
Similarly, we have
Now we can sum the fractions:
Answer:
Option D) The prisoner is actually guilty and the jury sets him free.
Step-by-step explanation:
We are given the following in the question:
Null Hypothesis:
The null hypothesis states that the prisoner is innocent
Alternate Hypothesis:
The alternate hypothesis states that the prisoner is guilty and not innocent.
Type II error:
It is the type error made when we fail to reject the ll hypothesis when it is actually false.
That is we accept a false null hypothesis.
Thus a type II error in the above scenario will be to accept that the prisoner is innocent (accepting the null hypothesis) when actually he is guilty( the alternate hypothesis)
Thus, type II error would be setting free a guilty prisoner.
Option D) The prisoner is actually guilty and the jury sets him free.