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jeka94
3 years ago
12

Ví dụ 1.5. Một người đi mua hàng 3 lần. Xác suất lần đầu mua được hàng tốt là 0,7.

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

a) 0.50575,

b) 0.042

Step-by-step explanation:

Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.

If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).

And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:

a) All three times the person bought good goods.

P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =

(0.7)(0.85)(0.85) =

0.50575      

b) Only the second time that person buys a bad product.

P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =

(0.7)(1-0.85)(1-0.6) =

(0.7)(0.15)(0.4) =

0.042

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b. (-3, -2)

explanation:

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PLEASE HELP
alina1380 [7]

When the dice is rolled 14 times then from the given data the probability of 1,2,3,4,5,6 is 3/14,1/14,4/14,1/14,3/14,2,14.

Given Roll of dice and outcomes from 1 to 14 is 1,3,5,4,5,3,3,1,3,5,6,1,6,2.

From the given collected data we can find out number of times each number came when the dice is rolled.

Number of times 1 came=3

Number of times 2 came=1

Number of times 3 came=4

Number of times 4 came=1

Number of times 5 came=3

Number of times 6 came=2

The probabilities are in fraction form:

P(1)=3/14

P(2)=1/14

P(3)=4/14

P(4)=1/14

P(5)=3/14

P(6)=2/14

The probabilities in decimal form:

P(1)=0.21

P(2)=0.07

P(3)=0.28

P(4)=0.07

P(5)=0.21

P(6)=0.14

The probabilities in percentage:

P(1)=21%

P(2)=7%

P(3)=28%

P(4)=7%

P(5)=21%

P(6)=14%

Hence the probabilities are 3/14,1/14,4/14,1/14,3/14,2,14.

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2 years ago
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Answer:

h = 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

0.75h + 3 = 12

<u>Step 2: Solve for </u><em><u>h</u></em>

  1. Subtract 3 on both sides:                    0.75h = 9
  2. Divide 0.75 on both sides:                  h = 12

<u>Step 3: Check</u>

<em>Plug in h into the original equation to verify it's a solution.</em>

  1. Substitute in <em>h</em>:                    0.75(12) + 3 = 12
  2. Multiply:                               9 + 3 = 12
  3. Add:                                     12 = 12

Here we see that 12 does indeed equal 12.

∴ h = 12 is a solution of the equation.

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