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Pie
3 years ago
9

How many electrons does a single hydrogen gain or lose in the following reaction? H2 + O2 - H20

Chemistry
1 answer:
nirvana33 [79]3 years ago
4 0

Answer:

One electron per single hydrogen atom.

Explanation:

Hello!

In this case, given the reaction:

H_2+O_2\rightarrow H_2O

Whereas we can identify the following half-reaction for hydrogen:

H_2^0\rightarrow H_2^+

Whereas we see that each single hydrogen atom gains one electron in order to go from 0 to +1, which is also related to an oxidation half-reaction.

Best regards!

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3 0
3 years ago
What is the density of a plastic ball that has a volume of 6cm) and a mass of 12g?<br> 50 cm3
marissa [1.9K]

Answer:

2 g/cm³

Explanation:

4 0
2 years ago
What's the oxidation number of Li in LiNO3
Studentka2010 [4]

+1

Explanation:

To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.

The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit

The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.

The algebraic sum of all oxidation number of atoms in a neutral compound is zero;

   The radical NO₃ has a formal charge of -1;

 let the oxidation number of Li = x

 x + (-1) = 0

  x = + 1

learn more:

Oxidation number brainly.com/question/10017129

#learnwithBrainly

4 0
2 years ago
Salt is often added to water to raise the boiling point to heat food more quickly. if you add 30.0g of salt to 3.75kg of water,
sammy [17]

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

<h3>What is the boiling-point elevation?</h3>

Boiling-point elevation describes the phenomenon that the boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.

  • Step 1: Calculate the molality of the solution.

We will use the definition of molality.

b = mass solute / molar mass solute × kg solvent

b = 30.0 g / (58.44 g/mol) × 3.75 kg = 0.137 m

  • Step 2: Calculate the boiling-point elevation.

We will use the following expression.

ΔT = Kb × m × i

ΔT = 0.512 °C/m × 0.137 m × 2 = 0.140 °C

where

  • ΔT is the boiling-point elevation
  • Kb is the ebullioscopic constant.
  • b is the molality.
  • i is the Van't Hoff factor (i = 2 for NaCl).

The normal boiling-point for water is 100 °C. The boiling-point of the solution will be:

100 °C + 0.140 °C = 100.14 °C

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

Learn more about boiling-point elevation here: brainly.com/question/4206205

7 0
2 years ago
PLEASE HELP ASAP I EILL GIVE 100 POINTS!!! Kristy is on the track team. She runs the one kilometer race by going four times arou
qaws [65]

Answer:A

Explanation:

5 0
2 years ago
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