Answer:
A. Concentration of diluted acid = 0.00389 M
B. Concentration of OH- in AgOH solution = 0.00012 M
Explanation:
A. Using the dilution formula: C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
From the data provided, C1 = 0.09714 M, V1 = 10.0 mL, V2 = 250.0 mL and C2 = ?
Making C2 subject of the formula above; C2 = C1V1/V2
C2 = 0.09714 M × 10 / 250 = 0.00389 M
B. Equation of the neutralization reaction is given below:
HCl + AgOH ---> AgCl + H₂O
From the equation, 1 mole of acid neutralizes 1 mole of base
Using the titration formula; CaVa/CbVb = na/nb
Where Ca is the concentration of the acid HCl = 0.00389 M
Va is the volume of acid = 7.93 mL
Cb is the concentration of base, AgOH = ?
Vb is volume of base = 250.0 mL
na/nb = mole ratio of acid and base = 1
Making Cb subject of the formula in the equation above; Cb = CaVa/Vb
Cb = 0.00389 M × 7.93 / 250
Cb = 0.00012 M
