Carla works two jobs-one as a teacher and another as an editor for a total of 40 hours each week. She makes $24 per hour as a te
1 answer:
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On the x axis means that the y value is 0 or the point is (x,0)
distance formula
D=
we know that distance is 5
the first point is (x1,y1)
the (x2,y2) is (x,0)
so
D=5
x1=-8
y1=3
x2=x
y2=0
5=
5=
5=
5=
square both sides
25=
minus 25 both sides
0=x^2+16x+48
factor
0=(x+4)(x+12)
set each to zero
x+4=0
x=-4
x+12=0
x=-12
the points are
(-4,0) and (-12,0)
distance formula
D=
we know that distance is 5
the first point is (x1,y1)
the (x2,y2) is (x,0)
so
D=5
x1=-8
y1=3
x2=x
y2=0
5=
5=
5=
5=
square both sides
25=
minus 25 both sides
0=x^2+16x+48
factor
0=(x+4)(x+12)
set each to zero
x+4=0
x=-4
x+12=0
x=-12
the points are
(-4,0) and (-12,0)
Answer: Choice B)
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Work Shown:
This shows why choice B is the answer.
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Explanation:
- In the second step, I multiplied top and bottom by
- This is so we can apply the difference of squares rule in step 3. The difference of squares rule is (x-y)(x+y) = x^2-y^2.
- In step 4, the square roots cancel out with the squaring operation. The two operations are inverses of one another, which is why they cancel.
So in general, if the denominator is and you want to rationalize the denominator, then you should multiply top and bottom by
. The same applies in reverse as well.
This leads to the denominator becoming
Keep in mind that and
-1 is the rest, because its degree is smaller than that of the divisor and therefore can not continue dividing.
x ^ 3 - x ^ 2 + x -1 is the quotient.
I attach the solution
x ^ 3 - x ^ 2 + x -1 is the quotient.
I attach the solution