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sesenic [268]
3 years ago
7

How will amino acids made with isotopes help scientists to answer this question?

Chemistry
1 answer:
Wewaii [24]3 years ago
5 0

Answer:

Proteins are made up of 20 amino acids. How an Isotope Technique Helps Determine Protein Quality. However be produced by the body and therefore are participated in the labelling process.

Explanation:

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Which subatomic particles are found in the nucleus of a lithium atom?
marin [14]

Answer:

Protons, neutrons, electrons..

Explanation:

Protons and neutrons consist of quarks which are stuck together by tiny things called gluons.

Hope this helps! :)

4 0
3 years ago
Which process do ribosomes perform​
Llana [10]
Synthesizes (makes) proteins to be used by the cell. Not membrane bound
8 0
4 years ago
Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lith
alexandr402 [8]

The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>
  • Let Li6 be isotope A
  • Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>
  • Molar mass of isotope A (Li6) = 6.02 u
  • Molar mass of isotope B (Li7) = 7.02 u
  • Atomic mass of lithium = 6.94 u
  • Abundance of A = A%
  • Abundance of B = (100 - A)%

Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

6.02A% + 702 - 7.02A% = 694

Collect like terms

6.02A% - 7.02A% = 694 - 702

-A% = -8

A% = 8%

Thus,

Abundance of B = (100 - A)%

Abundance of B = (100 - 8)%

Abundance of B = 92%

SUMMARY

  • Abundance of A (Li6) = 8%
  • Abundance of B (Li7) = 92%

From the above, isotope Li7 is more abundant.

Learn more about isotope:

brainly.com/question/24311846

#SPJ1

4 0
2 years ago
What are the characteristics of a good (effective) window cleaner?
Readme [11.4K]

Removes smudges, leaves no after streaks

8 0
3 years ago
Ni-cad (nickel–cadmium) batteries have a slightly lower cell potential than the common alkaline value of 1.5 v normally used in
Lorico [155]
The half-reaction are:

Cd ---> Cd(OH)₂
The oxidation number of Cd changed from 0 to +2. So, the number of mol electron transferred here is 2.

NiO(OH) --> Ni(OH)₂
The oxidation number of Cd changed from +3 to +2. So, the number of mol electron transferred here is 1.

Now, the greatest common factor would be 2. So, we use n=2 for the formula for ΔG°. F is Faraday's constant equal to 96,485 J/mol e.

ΔG° = nFE° = (2)(96,485)(1.5) =<em> 289,455 J</em>


6 0
3 years ago
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