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Alenkinab [10]
2 years ago
8

What is the total number of atoms of magnesium and phosphorus in 3Mg3(PO4)2?

Chemistry
1 answer:
JulsSmile [24]2 years ago
4 0
Since the given formula is . According to cross method formula, magnesium has +2 charge so, is multiplied by 2.
Thus, 1 molecule of magnesium phosphate will contain 2 atoms of phosphorus.
Therefore, three molecules of magnesium phosphate contains following number of atoms.
Mg = 9
P = 6
O = 24
Hence, we can conclude that there are 6 atoms of phosphorus in three molecules of magnesium phosphate, .
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4 0
2 years ago
Write the formula of the conjugate acid of HCO₂⁻.
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Taking into account the Brønsted-Lowry acid-base theory, the conjugate acid of HCO₂⁻ is H₂CO₂.

<h3>Brønsted-Lowry acid-base </h3>

The Brønsted-Lowry acid-base theory (or the Brønsted-Lowry theory) identifies acids and bases based on whether the species accepts or donates protons or H⁺.

According to this theory, acids are proton donors while bases are proton acceptors. That is, an acid is a species that donates an H⁺ proton while a base is a chemical species that accepts an H⁺ proton from the acid.

So, reactions between acids and bases are H⁺ proton transfer reactions.

<h3>Conjugate base and conjugate acid</h3>

Then, a conjugate base is an ion or molecule resulting from the acid that loses the proton, while a conjugate acid is an ion or molecule resulting from the base that gains the proton:

acid + base ⇄ conjugate base + conjugate acid

<h3>Conjugate acid of HCO₂⁻</h3>

Like a conjugate acid is an ion or molecule resulting from the base that gains the proton, the conjugate acid of HCO₂⁻ is H₂CO₂.

Learn more about the Brønsted-Lowry acid-base theory:

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7 0
2 years ago
If a chemist has 17.8 moles of N2H4O3, what is the mass of the sample?<br><br> show work plz
harkovskaia [24]

(\frac{17.8mole}{1} )( \frac{66grams}{1mole} ) \:  \:  \:  \:  17.8 \times 66 = 1.17 \times  {10}^{3} grams
the way that you get 66 is by adding he atomic mass unit of each atom in the formula. so N2 is 14 + 14 H4 is 1 * 4 and 03 is 16 * 3
4 0
2 years ago
In a titration experiment, 31.4 mL of 1.120 M HCOOH is neutralized by 16.3 mL of Ba(OH)2. What is the concentration of the Ba(OH
11Alexandr11 [23.1K]

Answer : The concentration of the Ba(OH)_2 solution is, 2.16 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCOOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2.

We are given:

n_1=1\\M_1=1.120M\\V_1=31.4mL\\n_2=2\\M_2=?\\V_2=16.3mL

Putting values in above equation, we get:

1\times 1.120M\times 31.4mL=2\times M_2\times 16.3mL\\\\M_2=2.16M

Thus, the concentration of the Ba(OH)_2 solution is, 2.16 M

7 0
3 years ago
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