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3 years ago

What is the total number of atoms of magnesium and phosphorus in 3Mg3(PO4)2?

1 answer:

4 0

Since the given formula is . According to cross method formula, magnesium has +2 charge so, is multiplied by 2.
Thus, 1 molecule of magnesium phosphate will contain 2 atoms of phosphorus.
Therefore, three molecules of magnesium phosphate contains following number of atoms.
Mg = 9
P = 6
O = 24
Hence, we can conclude that there are 6 atoms of phosphorus in three molecules of magnesium phosphate, .

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What is the maximum amount of water (in grams) that can be removed from 15ml of toluene by the addition?

Nataly [62]

Complete Question

Magnesium sulfate forms a hydrate with the formula $MgSO_4. 7H_20$ . What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of $MgSO_4$ is 120.4 g/mol; H20 = 18 g/mol.

Answer:

The value is $z = 0.2093 \ g$ of $H_2O$

Explanation:

From the question we are told that

The volume of toluene is $V = 15 mL$

The mass of anhydrous magnesium sulfate is $m = 200m g = 200 *10^{-3} \ g$

The formula of the hydrate is $MgSO_4. 7H_20$

The molar mass of $MgSO_4$ is $z =120.4 \ g/mol$

From the formula given we see that

1 mole of $Mg SO_4$ wil remove 7 moles of $H_2O$ to for the given formula

Hence

120.4 g (1 mole) will remove 7 moles (7 * 18 g = 126 g ) of $H_2O$ to for the given formula

Therefore 1 g of $Mg SO_4$ x g of $H_2O$

$x = \frac{x]126 * 1}{ 120.4 }$

=> $x = 1.0465 \ g$

From our calculation we obtained that

1 g of $Mg SO_4$ will remove $x = 1.0465 \ g$ of $H_2O$

Then

$200 *10^{-3} \ g$ of $Mg SO_4$ will remove z g of $x = 1.0465 \ g$ of $H_2O$

$z = 200 *10^{-3} * 1.0465$

=> $z = 200 *10^{-3} * 1.0465$

=> $z = 0.2093 \ g$ of $H_2O$

6 0

3 years ago

A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o

Andre45 [30]

Answer:

* $x_{CH_3OH}=0.0425$

* $\%m/m_{CH_3OH}=7.31\%$

* $m=2.46m$

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

$x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}$

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

$n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O$

Hence, mole fraction is:

$x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425$

Next, mass percent is:

$\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%$

And the molality, considering the mass of water in kg (0.185 kg):

$m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m$

Regards.

7 0

3 years ago

Please Help ASAP! View Attached Pictures. I don't understand this.

barxatty [35]

Answer:

Answers with the explanation.

Explanation:

Surprisingly all of the answers were C for some reason:

14. C (Extensive Properties include mass, volume and length)

15. C (Boiling/Melting/Freezing point are examples of physical change)

16. C (Malleability is how bendable an object is, therefore a physical change)

17. C (For Example, Water only forms Water Vapor when it´s heated up)

5 0

3 years ago

Read 2 more answers

KOH (aq) + HC2H3O2 (aq) ?

Radda [10]

KOH + HC₂H₃O₂ = H₂O + KC₂H₃O₂

hope this helps!

3 0

3 years ago

Draw the best lewis structure for h 2 co 3 and calculate the formal charge on carbon.

schepotkina [342]

The Lewis structure of Carbonic Acid (H₂CO₃) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with hydroxyl groups.

Formal Charge;
Formal charge is caculated as,

Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]

Formal charge on Carbon;

Formal charge = 4 - [ 0 + 8/2]

Formal charge = 4 - [4]

Formal charge = Zero

7 0

3 years ago