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Alenkinab [10]
3 years ago
8

What is the total number of atoms of magnesium and phosphorus in 3Mg3(PO4)2?

Chemistry
1 answer:
JulsSmile [24]3 years ago
4 0
Since the given formula is . According to cross method formula, magnesium has +2 charge so, is multiplied by 2.
Thus, 1 molecule of magnesium phosphate will contain 2 atoms of phosphorus.
Therefore, three molecules of magnesium phosphate contains following number of atoms.
Mg = 9
P = 6
O = 24
Hence, we can conclude that there are 6 atoms of phosphorus in three molecules of magnesium phosphate, .
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Can someone help Plz
Marrrta [24]

Answer: A. 1.60 liters

Explanation:

2Na_2O_2+2CO_2\rightarrow 2Na_2CO_3+O_2

As can be seen from the balanced chemical equation, 2 moles of CO_2 produce 1 mole of O_2.

According to Avogadro's law, every 1 mole of the gas occupies 22.4 liters at STP.

Thus 2 moles of CO_2 occupies 22.4\times 2=44.8L at STP and produce 1 mole of O_2 i.e. 22.4 L

44.8 L of CO_2 will produce 22.4 L of O_2

Thus 3.20L of CO_2 will produce \frac{22.4}{44.8}\times 3.20=1.60L



6 0
2 years ago
What will happen to a test dummy during a crash test if its seatbelt is not buckled? The test dummy will stop when the car stops
creativ13 [48]
<span>The test dummy will continue forward until it makes contact with another object.</span>
7 0
3 years ago
Read 2 more answers
Which form of energy can be connected closely to climate change?
Art [367]

Answer:

COAL

Explanation:

4 0
3 years ago
_Li + __F2 → _LIF<br> How do I balance this?
Semmy [17]

Answer:

 2Li   +   F₂    →    2LiF

Explanation:

The reaction expression is given as:

          Li   +   F₂    →     LiF

We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.

 Let use a mathematical approach to solve this problem;

  Assign variables a,b and c as the coefficients that will balance the expression:

             aLi   +  bF₂    →     cLiF

Conserving Li: a  = c

                   F:  2b  = c

          let a = 1, c  = 1 and b  = \frac{1}{2}  

  Multiply through by 2;

        a  = 2, b = 1 and c  = 2

               2Li   +   F₂    →    2LiF

 

5 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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