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myrzilka [38]
3 years ago
8

A bucket contains 4 red balls that are numbered 1, 2, 3, 4. It also contains 6 black balls that are numbered 5, 6, 7, 8, 9, 10.

Two balls are drawn from the bucket, one at a time, without replacement. Use this information to answer the following probability questions. Express answers as fractions, or round decimal answers to 4 decimal places. a. What is the probability that the first ball is even and the second ball is odd
Mathematics
1 answer:
Yakvenalex [24]3 years ago
6 0

The probability is 1/9

<em>We want to find the </em><em>probability </em><em>that the first drawn ball is even, and the second is odd.</em>

The probability of randomly drawing an even ball will be equal to the quotient between the number of balls with even numbers and the total number of balls in the bucket.

We have a total of 10 balls (4 red ones and 6 black ones)

and 5 of these have even numbers (2, 4, 6, 8, 10)

Then the probability of drawing a ball with an even number first is:

p = 5/10 = 1/5

now we want to get a ball with an odd number.

notice that we already got a ball with an even number and we did not replace it, so now there are 9 balls left in the bucket, 5 odd ones, and 4 even ones.

The probability of getting an odd ball is computed in the same way thana above, as the quotient between the number of balls with odd numbers (5) and the total number of balls in the bucket (9)

q = 5/9

The joint probability (the probability that these two events happen together) is equal to the product of the individual probabilities, so we will get:

P = p*q = (5/9)*(1/5) = 1/9

The probability is 1/9

If you want to learn more about this topic, you can read:

brainly.com/question/24280250

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3 years ago
Which number is prime 57, 63, 51, 67
gavmur [86]
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Read 2 more answers
Help I will give you 10 points please help
maxonik [38]

Answer:

Look Below

Step-by-step explanation:

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3 years ago
surveyor stands 100 m from the base of a tower on which an antenna stands. He measures the angles of elevation to the top and bo
balu736 [363]

Answer: 36.3m

Step-by-step explanation:

To solve this, we can draw two triangle rectangles, where the distance between the man and the base of the tower is one of the cathetus, the adjacent one, the height will be the opposite cathetus.

The triangle where the elevation angle is 58° is associated with the height of the tower without the aerial

The other triangle, where the elevation angle is 63° is associated with the height of the tower with the aerial.

Then we can calculate those two heights, then compute the difference, and the difference will be equal to the height of the aerial.

In both cases we want to calculate the opposite cathetus, then we should use the relation:

Tan(θ) = (Op. cath)/(Adj. cath)

The height without the aerial is h1, let's find it:

Tan(58°) = h1/100m

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The height with the aerial is h2, let's find it:

Tan(63°) = h2/100m

Tan(63°)*100m = h2 = 196.3m

Then the height of the aerial will be:

h2 - h1 =  196.3m -  160m = 36.3m

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You guyss know it's math
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The coefficient of X is -2

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