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choli [55]
3 years ago
8

What type of transformation takes the graph of f(x)=|x| to the graph of g(x)=−3+|x|?

Mathematics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

vertical translation of 3 units down

Step-by-step explanation:

we have

f\left(x\right)=\left|x\right| ----> the parent function

The vertex of f(x) is the point (0,0)

g\left(x\right)=-3+\left|x\right| ----> the transformed function

The vertex  of g(x) is the point (0,-3)

so

The rule of the translation is

f(x) -----> g(x)

(0,0) ----> (0,-3)

(x,y) ----> (x,y-3)

That means ---> The translation is 3 units down

see the attached figure to better understand the problem

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Which angle is vertical <EFA
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<u>Angles that are vertical are basically neighbors that are across from each other (numbers across from each other). </u>

Angle <u><CFD</u> would be vertical to <EFA.


5 0
3 years ago
A number divided by 80 has a quotient of 7 with remainder of 4
Harlamova29_29 [7]

n-\text{the number}\\\\n:80=7+R4\Rightarrow n=80\cdot7+4\\\\n=564

5 0
4 years ago
What is the maximum value of the objective function, P, with the given constraints?
maksim [4K]

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

P=20x+35y

Constraints,

x+y \leq 12

5x+y \leq 20\\x \geq 0\\y \geq 0

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

P=20x+35y

  • Point (0,0)

P=20(0)+35(0)=0

P=20x+35y

  • Point (0,12)

P=20(0)+35(12)=420

  • Point (2,10)

P=20(2)+35(10)=40+350=390

  • Point (4,0)

P=20(4)+35(0)=80

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

8 0
3 years ago
Help me pls I would really appreciate it
Paul [167]
The first the last and the 2nd last
4 0
3 years ago
Read 2 more answers
A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t
Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = \binom{n}{k}p^{K}q^{n-k}

In this formula n = number of trials

                        k = number of success

                        (n-k) = number of failures

                         p = probability of success in one trial

                         q = (1-p) = probability of failure in one trial

In this sum n = 5

                  k = 2

number failures (n-k) = (5-2) = 3

                            p = 2% which can be written as .02

                            q = 98% Which can be written as .98

Now putting these values in the formula

                        P = \binom{5}{2}(.02)^{2}(.98)^{5-2}

                        P = \binom{5}{2}(.02)^{2}(.98)^{3}

                   \binom{5}{2}= 5!/3!2!    

                                              = 5×4×3×2×1/3×2×1×2×1

                                              = 5×2 =10

                                       P = 10×(.02)²×(.98)³

                                          = .0037 or .37%

4 0
4 years ago
Read 2 more answers
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