**Answer: hello your question is incomplete below is the missing part **

Determine the proportion of radishes grown without fertilizers with weight less than 50grams

**answer** : p( x < 50 ) = 0.84

**Step-by-step explanation:**

**Radish grown in without fertilizers ( normally distributed )**

mean = 40 g

standard deviation = 10 g

**Radish grown with fertilizers ( normally distributed ) **

Mean = 140 g

standard deviation = 40 g

<u>Determine the proportion of radishes grown without fertilizers with weight less than 50 grams </u>

lets assume x = radish without fertilizers

y = radish with fertilizers

hence

p( x < 50 ) = P ( (x-μ / б) < )

= p ( z < 1 ) = 0.5 + p ( 0 < z < 1 )

p( x < 50 ) = 0.5 + 0.3413 = 0.8413

**attached below is the distribution related to this solution **