A=4 c=3 a-c? AAAAAAAAAAAAA

System of quadratic x² - y² = 4 x² + y² = 4

const2013 [10]

Answer: (2,0),(−2,0)

Step-by-step explanation:

5 0

2 years ago

If f(x)=(1/8)(8^x) what is f(3)? A. 1/512 B. 1/64 C. 512 D. 64

cestrela7 [59]

Hi there!

Let's solve this problem step by step!
$f(x) = \frac{1}{8} (8 {}^{x})$

To find f(3) we must substitute x = 3 into the formula.
$f(3) = \frac{1}{8} (8 {}^{3} )$

Now we use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Work out the exponents inside the parenthesis first.
$f(3) = \frac{1}{8} \times 512$

And finally multiply.
$f(3) = \frac{1}{8} \times \frac{512}{1} = \frac{512}{8} = 64$

Hence, the answer is D. 64.
~ Hope this helps you!

4 0

2 years ago

Read 2 more answers

Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random

Katen [24]

Answer:

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

Step-by-step explanation:

Given

$n = 200$

$x_1 = 34$ -- City C

$x_2 = 54$ --- City K

Required

Determine the 90% confidence interval

This is calculated using:

$CI = \bar x \± z\frac{\sigma}{\sqrt n}$

Calculating $\bar x$

$\bar x = \bar x_1 - \bar x_2$

$\bar x = \frac{x_1}{n} - \frac{x_2}{n}$

$\bar x = \frac{34}{200} - \frac{54}{200}$

$\bar x = 0.17 - 0.27$

For a 90% confidence level, the z-score is 1.65. So:

$z = 1.65$

Calculating the standard deviation $\sigma$

$\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }$

So:

$\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }$

$\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}$

So:

$CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}$

$CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}$

7 0

2 years ago

Someone help me asap!

Sergeeva-Olga [200]

Answer: 5/2

5/6 / 1/3 = 2.5

2.5 in fraction = 5/2

5 0

2 years ago

Read 2 more answers

Triangle A″B″C″ is formed by a reflection over x = −1 and dilation by a scale factor of 4 from the origin. Which equation shows

juin [17]

Answer:

$\frac{AB}{A''B''} = \frac{1}{4}$

Step-by-step explanation:

Given the information:

A'B'C' reflection over x = −1
dilation by a scale factor of 4 from the origin

<=> the two triangles are similar to each other, triangles are similar if they have the same shape, but can be different sizes, so A″B″C″ is 4 time bigger than ABC

=> the relationship between ΔABC and ΔA″B″C″

= $\frac{AB}{A''B''} = \frac{1}{4}$

We choose C.

Hope it will find you well.

7 0

3 years ago