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Mama L [17]
3 years ago
5

How to factor a quadratic

Mathematics
1 answer:
Romashka [77]3 years ago
3 0

Answer:

To factor a quadratic polynomial use the equation

Step-by-step explanation:

F(x) = k{x2 - (sum of zeroes)x + (product of zeroes)}

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Answer:

314.2

Step-by-step explanation:

A = π r2

10x10 = 100

100 x 3.1416 (Only a little bit of pi)

314.15927

314.2

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Determine whether the statement below is always, sometimes, or never true. Justify your reasoning. The Expressions x - 3 and y -
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Sometimes true: when x = y it's true ; when x ≠ y it's not true.
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HELP ASAP NOW!
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30 minutes for each girl. 30min x 4girls = 120min for all girls. 120/60=2 hrs
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Find the length of line AC. Use that length to find the length of line CD. What is the length of line CD? Round to the nearest t
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The mean mark of a group of 10 boys is 58. If the mean of 7 of them is 61, what is the mean of the remaining 3 boys
Nesterboy [21]

Answer:

The mean of the remaining 3 boys is 51.

Step-by-step explanation:

The mean mark of the entire group (p_{10}), dimensionless, is:

p_{10} = \frac{1}{10}\cdot \Sigma_{i = 1}^{10} x_{i} (Eq. 1)

(p_{10} = 58)

\frac{1}{10}\cdot \Sigma_{i=1}^{10} x_{i} = 58 (Eq. 1b)

Where x_{i} is the mark of the i-th boy, dimensionless.

In addition, we know the following mean marks from statement:

p_{7} = \frac{1}{7} \cdot \Sigma_{i = 1}^{7} x_{i} (Eq. 2)

(p_{7} = 61)

\frac{1}{7}\cdot \Sigma_{i=1}^{7} x_{i} = 61 (Eq. 2b)

p_{3} = \frac{1}{3}\cdot \Sigma_{i=8}^{10}x_{i} (Eq. 3)

Where:

p_{7} - Mean mark of the first 7 boys, dimensionless.

p_{3} - Mean mark of the remaining 3 boys, dimensionless.

By applying sum properties in (Eq. 1b) and using (Eq. 2b) and (Eq. 3), we obtain the mean of the remaining 3 boys:

\frac{1}{10}\cdot [\Sigma_{i = 1}^{7}x_{i}+\Sigma_{i=8}^{10}x_{i}] = 58

\frac{1}{10}\cdot [7\cdot (61)+3\cdot p_{3}] = 58

7\cdot (61) + 3\cdot p_{3} = 580

3\cdot p_{3} = 153

p_{3} = \frac{153}{3}

p_{3} = 51

The mean of the remaining 3 boys is 51.

7 0
3 years ago
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