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olganol [36]
3 years ago
7

Write an equation of a like that passes through the points (9,5) and (6,7)

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

y=-2/3x+11

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-5)/(6-9)

m=2/-3

m=-2/3

y-y1=m(x-x1)

y-5=-2/3(x-9)

y=-2/3x+18/3+5

y=-2/3x+6+5

y=-2/3x+11

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The Sum of twice a number and 5 is at most 15. What are the possible values for the number?
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2x+5\le 15

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2x+5\le 15\\ \\ 2x\le 15-5\\ \\ 2x\le 10\\ \\ x\le \frac { 10 }{ 2 } \\ \\ x\le 5

x\quad \in \quad \left[ -\infty ,5 \right]

If the number is a natural number. The values it can take is, x\quad \in \quad \left[ 0,1,2,3,4,5 \right]


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2 years ago
A wire is stretched from the ground to the top of an antenna tower. The wire is 15 feet long. The height of the tower is 3 feet
Mariana [72]

The distance d is 9 ft and the height is 12ft.

<h3>How to find the distance and the height?</h3>

Here we can model the situation with a right triangle, where the length of the wire is the hypotenuse.

The height is one cathetus and the distance is the other catheti.

Let's define:

  • h = height
  • d = distance.
  • hypotenuse = 15ft

We know that the height of the tower is 3 ft larger than the distance, then:

h = d + 3ft

Now we can use the Pythagorean theorem, it says that the sum of the squares of the cathetus is equal to the square of the hypotenuse.

Then:

d^2 + (d + 3ft)^2 = (15ft)^2

Now we can solve this equation for d:

d^2 + d^2 + 6ft*d + 9ft^2 = (15ft)^2\\\\2d^2 + 6ft*d - 216 ft^2 = 0\\\\d^2 + 3ft*d - 108ft^2 = 0

Then the solutions are:

d = \frac{-3ft \pm \sqrt{(3ft)^2 - 4*(-108ft^2)} }{2} \\\\d = \frac{-3ft \pm 21ft }{2}

We only take the positive solution:

d = (-3ft + 21ft)/2 = 9ft

And the height is 3 ft more than that, so:

h = 9ft + 3ft = 12ft

The distance d is 9 ft and the height is 12ft.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

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