I hope this helps you
I need help with #'s 59, 63, 67, and 71 PLEASE!!!I need to find the domain!!
1 answer:
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Answer:
59. t ≥ -1
63. x ≤ -1/2
67. (x ≤ 0) ∪ (x ≥ 6)
71. x > 1/2
Step-by-step explanation:
The domain is the set of values of x where the function is defined. In rational functions it excludes any values of x that make the denominator zero. When even-index roots are involved, it excludes values of x that make the argument of the root function negative.
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59. t+1 ≥ 0 ⇒ t ≥ -1
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63. 1 -2x ≥ 0 ⇒ x ≤ -1/2
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67. x² -6x ≥ 0 ⇒ x(x -6) ≥ 0 ⇒ (x ≤ 0) ∪ (x ≥ 6)
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71. 2x -1 > 0 ⇒ x > 1/2 . . . . note we left off the =0 case for this one
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The attachment is a plot of the g(x) in 67. You can see that it is undefined for 0 < x < 6.
As you can see, a graphing calculator can be helpful in identifying the domain. Of course, any vertical asymptotes are excluded, as are any "holes" in a function.
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Answer:
'5n' is the correct answer.
Step-by-step explanation:
Let 'n' be any integer i.e. a number from the set {....., -3,-2,-1,0,1,2,3, ..... }
so 'n' can be termed as the variable here because its value can change and can be any value from the above set.
A number 'q' that can be divided by a a given number 'p' can be written as:
When divided by 'p' :
So, The number 'q' is completely divisible by 'p' leaving 'n' as the quotient.
Using this concept, let us solve the questions:
a) Using 'n' as the variable, a number that is divisible by 5 can be written as:
Read more on Brainly.com - brainly.com/question/16919676#readmore