Answer:
12 feet per second.
Step-by-step explanation:
Please consider the complete question.
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented
.
What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?
We will use average rate of change formula to solve our given problem.








Therefore, Spot's average rate of ascent is 12 feet per second.
The Jasmine result is the good one because 1 mégas meter=1 000 000
Answer:
y = 7/5x + 4
Step-by-step explanation:
use the slope from the equation -5/7 and take the negative reciprocal to get the perpendicular slope = 7/5. Then use the equation y=mx+b. Plug in x and y from the point given and the new slope and solve for b.
(-3) = (7/5)(-5) + b, (-3) = -7 + b, add 7 to both sides. b = 4. Rewrite the equation now to be y = 7/5x + 4
Answer:
Step-by-step explanation:
<u>Given </u>
<u>In the first quadrant both sine and cosine are positive, so as tangent.</u>
- tanθ = sinθ / cosθ =
θ / cosθ =
/ 4/5 =
/ 4/5 = - 3/5*5/4 =
- 3/4
If you are being asked to simplify, just combine like terms; such as, all the g’s and all the numbers so, your answer should look something like: 7g+6