Answer:
4x +10 + 3x +2 = 180 (since they're supplementary, the angles together =180)
7x +12 =180 (combine like terms on left side, and subtract 12 from both sides)
7x = 168 (divide both sides by 7 to isolate x)
x= 24
angle 1 = 4(24)+10 (plug x into the expression for each angle, and solve)
..................96 +10
angle 1 = 106 degrees (the measure of the first angle)
angle 2 = 3(24) +2
..................72 +2
angle 2 = 74 (the measure of the second angle)
106 +74 =180 (the two add up to 180, so they're supplementary)
Step-by-step explanation:
I hope this helps :)
I'm assuming that the line is JKL in order of the points from left to right.
JK + KL = JL
(17-x) + (2x-7) = JL
Simplify.
10-x = JL
A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.
Use two points to find the slope
Answer:
Step-by-step explanation:
lets break down 120 to see what it is divisible by and see if any of those numbers are perfect squares.
120/2=60
120/3=40
120/4=30
we can stop there because 4 is a perfect square and 30 can not be reduced any further to produce a perfect square.
do not forget there is only one x so it must stay in side the radical.
your answer is 2sqrt(30x)
