Ask question

Ask question

All categories

3 years ago

8

Helppp I don't understand on how I am suppose to find the valuee

1 answer:

sp2606 [1]3 years ago

4 0

Graph those points given, in a cartesian plane grid,
that is, an x,y axis grid

and try to make a straight line from the leftmost, to
the rightmost, they don't really line up as a straight
line, so... try to draw a line that will cover "most of
the points", there will be a couple or so "outliers",
the line that "covers most of the points" is so-called
"best-fit" line, so, using that line, try to get what
"y" is, when x = 3

You might be interested in

Kolby decided he wanted to go to the amusement park. The amusement park charges $8.00 for entry and $1.40 for each ride.

dimulka [17.4K]

Answer:

He pays $8.00 regardless and $1.40 for each ride. When we see for each, we typically want to multiply.

A. $8.00 + $1.40 * r

If his parents gave him $26.00, then that is the most Kolby can spend.

$8 + $1.40 * r = $26

Subtracting 8 from both sides:

$1.40 * r = $18

Dividing both sides by 1.40:

r = 12.86

B. Since you can't ride part of a ride, Kolby can only ride 12 rides.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Multiplicative inverse of 21/49

Komok [63]

Answer:

49/21

Step-by-step explanation:

You just have to switch the numerator and denominator so you can cancel out the number from one side of the equation in a normal problem

5 0

3 years ago

What is the factorization of 121b^4-49

Nezavi [6.7K]

121^4-49

(11^2+7)(11^2-7) 1. 121. 49

11. × 11. 7 × 7

4 0

3 years ago

aev [14]

Answer:

D. No, because $P(A|B)=0.22$ and the $P(A) = 0.53$ are not equal.

Step-by-step explanation:

Given:

Probability of doing yard work is, $P(A)=53\%=0.53$

Probability of raining, $P(B)=68\%=0.68$

Probability of doing yard work and it raining is, $P(A\cap B)=15\%=0.15$

Now, two events A and B are independent if,

$P(A|B)=P(A);P(B|A)=P(B)$

Conditional probability of event A given that B has occurred is given as:

$P(A|B)=\frac{P(A\cap B}{P(B)}\\P(A|B)=\frac{0.15}{0.68}=0.22$

So, $P(A|B)=0.22\ and\ P(A)=0.53$

Since, $P(A|B)\ne P(A)$ , A and B are not independent events.

8 0

3 years ago

Refer to the image i couldnt copy it so the image is the quesstion<br><br> answer in true or false

Irina18 [472]

The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.

<h3>Is the equation in the image correct or incorrect?</h3>

For a quadratic equation of the form:

$y = a*x^2 + b*x + c$

By using the Bhaskara's formula, the solutions of the equation:

$0 = a*x^2 + b*x + c$

Are given by the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$

Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.

So the equation shown in the image is incorrect.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

6 0

2 years ago