11,050 divided by 26 is the remainder of 425. Fraction form it would be 425/1000. (in the 1000th decimal place) To reduce it, you would divide the numerator and denominator by 25 since 25 is the g<span>reatest common divisor. Therefore,</span> it would be 17/40.
Answer:
A darts player practices throwing a dart at the bull’s eye on a dart board. Her probability of hitting the bull’s eye for each throw is 0.2.
(a) Find the probability that she is successful for the first time on the third throw:
The number F of unsuccessful throws till the first bull’s eye follows a geometric
distribution with probability of success q = 0.2 and probability of failure p = 0.8.
If the first bull’s eye is on the third throw, there must be two failures:
P(F = 2) = p
2
q = (0.8)2
(0.2) = 0.128.
(b) Find the probability that she will have at least three failures before her first
success.
We want the probability of F ≥ 3. This can be found in two ways:
P(F ≥ 3) = P(F = 3) + P(F = 4) + P(F = 5) + P(F = 6) + . . .
= p
3
q + p
4
q + p
5
q + p
6
q + . . . (geometric series with ratio p)
=
p
3
q
1 − p
=
(0.8)3
(0.2)
1 − 0.8
= (0.8)3 = 0.512.
Alternatively,
P(F ≥ 3) = 1 − (P(F = 0) + P(F = 1) + P(F = 2))
= 1 − (q + pq + p
2
q)
= 1 − (0.2)(1 + 0.8 + (0.8)2
)
= 1 − 0.488 = 0.512.
(c) How many throws on average will fail before she hits bull’s eye?
Since p = 0.8 and q = 0.2, the expected number of failures before the first success
is
E[F] = p
q
=
0.8
0.2
= 4.
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Answer:
10 and 11
Step-by-step explanation:
Let the first integer be x.
Then the next one, since it's consecutive, must be (x+1).
The two equals 21. Thus:
Combine like terms:
Subtract 1 from both sides:
Divide both sides by 2:
So, the first integer is 10.
And the second integer is 10+1=11.
Answer:
What's the question? equals?
Step-by-step explanation:
8qх + 21ру + брx + 28qy
8qх + 28qy + брx + 21ру rearranged the terms to help factoring
4q(2x + 7y) + 3p(2x + 7y)
(2x + 7y)(4q + 3p) or (4q + 3p)(2x + 7y)
