219864070186 - 277409297400 = -57545227214 x 780498 = -4.4913935e+16 - 1274806769367926946610431 = -1.2748068e+24 x 3.6614422e+21 = -4.6676314e+45 - 437913 = -4.6676314e+45 - 88878 = -4.6676314e+45
Ф = 500 , 5,000
5,000 / ∞ x ∞ x ∞ = 5,000^+++∞/ 68307147 = 0.00007319878^+++∞ - 917 - 974 - 9 - 19344381 = -19346280.9999^+++∞
-4.6676314e+45 -19346280.9999^+++∞ = -4.6676314e+45^+++∞
I believe that will be your answer.
I tried my best.
Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
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Answer:
Step-by-step explanation:
a. sin^-1(sin theta) = theta
(1/sin)(sin theta) = theta
<em>the sines cross out</em> theta = theta
b. cos(cos^-1x) = x
cos(x/cos) = x
<em>the cosines cross out </em>x = x
