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omeli [17]
3 years ago
13

what happens to change the solubility when you added 6.0 M HCl to the second test tube with benzoic acid

Chemistry
1 answer:
shusha [124]3 years ago
8 0

Answer:

It becomes insoluble again.

Explanation:

The chemical equation showing the reaction between benzoic acid, and sodium hydroxide,NaOH is given below;

C6H5COOH + NaOH ------------------------> C6H5COO^- Na^+ + H2O.

The Benzoic acid, C6H5COOH is insoluble but when it reacted with 1M Sodium hydroxide, NaOH it changes to sodium benzoate, C6H5COO^- Na^+ which is more soluble than the benzoic acid.

C6H5COO^- Na^+ + HCl -------------------> C6H5COOH + NaCl.

When the sodium benzoate, C6H5COO^- Na^+ reacts with 6M HCl, it is converted back to benzoic acid which is insoluble. Hence, precipitation is observed.

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