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mr Goodwill [35]
3 years ago
14

Consider the temperature versus time graph below. I which region is the substance in both the solid phase and the liquid phase?

1 2 3 4

Chemistry
2 answers:
SVEN [57.7K]3 years ago
8 0

Answer:

2

Explanation:

The change of state occurs at a constant temperture and pressure. In the grahp we can see while the time passes, the temperature doesn't change.

The rect number 4 correspond to a liquid-gas phase

Rasek [7]3 years ago
4 0

Answer : The stage 2 shows the substance in both the solid phase and the liquid phase.

Explanation :

In the given phase diagram,

Stage 1 : It shows the solid state of a substance.

Stage 2 : It shows the melting and freezing process of a substance. It means that when the phase changes from solid state to liquid state at constant temperature is know as melting process and when the phase changes from liquid state to solid state at constant temperature is know as freezing process.

Stage 3 : It shows the liquid state of a substance.

Stage 4 : It shows the evaporation and condensation process of a substance. It means that when the phase changes from liquid state to gaseous state at constant temperature is know as evaporation process and when the phase changes from gaseous state to liquid state at constant temperature is know as condensation process.

Stage 5 : It shows the gaseous state of a substance.

Hence, from the above information we conclude that the stage 2 shows the substance in both the solid phase and the liquid phase.

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dybincka [34]

Answer:

Option b. 0.048 M

Explanation:

We have the molecular weight and the mass, from sulcralfate.

Let's convert the mass in g, to moles

1 g . 1 mol / 2087 g = 4.79×10⁻⁴ moles.

Molarity is mol /L

Let's convert the volume of solution in L

10 mL . 1L/1000 mL = 0.01 L

4.79×10⁻⁴ mol / 0.01 L = 0.048 mol/L

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Determine the LIMITING reactant in the following balanced equation:
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Answer:

KBr is limiting reactant.

Explanation:

Given data:

Mass of  KBr =4g

Mass of Cl₂ = 6 g

Limiting reactant = ?

Solution:

Chemical equation:

2KBr + Cl₂      →    2KCl + Br₂

Number of moles of KBr:

Number of moles = mass/molar mass

Number of moles = 4 g/ 119 gmol

Number of moles = 0.03 mol

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 6 g/ 70 gmol

Number of moles = 0.09 mol

Now we will compare the moles of reactant with product.

              KBr            :            KCl

                2              :              2

            0.03            :            0.03

             KBr            :              Br₂

                2             :               1

             0.03           :          1/2×0.03= 0.015

               Cl₂             :            KCl

                 1              :              2

            0.09            :           2/1×0.09 = 0.18

               Cl₂             :              Br₂

                1              :               1

             0.09           :            0.09

Less number of moles of product are formed by the KBr thus it will act as limiting reactant while Cl₂  is present in excess.

5 0
3 years ago
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7 0
3 years ago
What is the molarity of a solution made by adding 0.720 mole of NaOH to 2.40 liters of water
WITCHER [35]

Answer:

Molarity = 0.3 M

Explanation:

Given data:

Moles of NaOH = 0.720 mol

Volume of water = 2.40 L

Molarity = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 0.720 mol / 2.40 L

Molarity = 0.3 mol/L

Molarity = 0.3 M

7 0
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