Answer:
Olivia is hosting a dinner party in her garden. She has hired caterers to serve dinner. The caterers charge a fee to set-up the dinner and $3 per person attending. The cost for 10 dinner guests is $70. Write an equation showing the cost of the dinner party as a function of the number of guests
Step-by-step explanation:
Length of the original ribbon = 2/3 yard
Length of the ribbon in which the actual ribbon has to be cut = 1/12 yards
The above information's are already given in the question. It is required to find the number of pieces that the ribbon can be cut with the length that is already mentioned.
Then
Number of pieces that will be there = (2/3)/(1/12)
= (2 * 12)/3
= 24/3
= 8
So the actual ribbon can be cut into 8 pieces and each piece will have a length of 1/12 yards. Hopefully the procedure for doing this problem is clear to you. this is the easiest method for attempting these kind of problems.
Answer: discrete.
Step-by-step explanation:
Discrete variable
It is a variable whose value is evaluated by counting.
Example: Number of books published in a month.
Continuous variable
It is a variable whose value is evaluated by measuring ( not countable).
Example: Distance: 1.52 m
Since the number of dental visits a randomly chosen person had for the past 5 years is a countable.
here, Variable: Let X =number of dental visits a randomly chosen person had for the past 5 years
So, the random variable described is discrete.
Information provided: Factor 18k-32k
First you have to find the greatest common factor between the two terms. You can first start by finding all the factors of 18 and 32:
18 --> 1,2,3,6,9,18
32 --> 1,2,4,8,16,32 (Here we kept 32 positive so it is easier to find the factors and you don't get confused by the subtraction symbol)
Out of all these factors, the only ones 18 and 32 have in common is 2. Now that you know the GCF (greatest common factor), you can now divide both terms by 2:
18k/2 = 9k
32k/2 = 16k
Since the constant/number 2 does not have a variable, it does not affect the variables in the other two terms only the constants.
Now you can put 9k and 16k where 18k and 32k:
9k-16k
You cant just leave 9k-16k by itself because all you are doing is putting the expression into simpler terms, not taking away parts of it. This is where the 2 you divided from both sides comes into play.
The only thing left to do is put parentheses around 9k-16k and put the 2 on the outside. Now your polynomial is factored:
2(9k-16k)
I hope this helps!
