Question

Without factoring, determine which of the graphs represents the function g(x)=21x2+37x+12 and which represents the function h(x)=21x2−37x+12. Explain your reasoning. The graph of represents the function g(x)=21x2+37x+12. The graph of represents the function h(x)=21x2−37x+12. Because c is positive, the constant terms in each factor must have signs. Because the function has a positive value for b, the constant terms in each factor will both be which results in Response area roots, and the graph of Response area has two Response area x-intercepts. Because the function has a negative value for b, the constant terms in each factor will both be which results in Response area roots, and the graph of Response area has two Response area x-intercepts.

Answer 1

Answer:

The graph which represents the function g(x) = 21·x² + 37·x + 12, is described as follows;

Because 'c' is positive, the constant terms in each factor must have the same signs

Because the function has a positive value for 'b', the constant terms in each factor will both be positive which results in negative  roots and the graph of the function, g(x) = 21·x² + 37·x + 12, has two negative x-intercepts

The graph which represents the function h(x) = 21·x² - 37·x + 12, we have is described as follows;

Because 'c' is positive, the constant terms in each factor must have the same signs

Because the function has a negative value for 'b', the constant terms in each factor will both be negative which results in positive roots and the graph of the function, g(x) = 21·x² + 37·x + 12, has two positive x-intercepts

Step-by-step explanation:

The given functions are;

g(x) = 21·x² + 37·x + 12

h(x) = 21·x² - 37·x + 12

For the graph which represents the function g(x) = 21·x² + 37·x + 12, we have

Because 'c' is positive, the constant terms in each factor must have the same signs

Because the function has a positive value for 'b', the constant terms in each factor will both be positive which results in negative  roots and the graph of the function, g(x) = 21·x² + 37·x + 12, has two negative x-intercepts

For the graph which represents the function h(x) = 21·x² - 37·x + 12, we have

Because 'c' is positive, the constant terms in each factor must have the same signs

Because the function has a negative value for 'b', the constant terms in each factor will both be negative which results in positive roots and the graph of the function, g(x) = 21·x² + 37·x + 12, has two positive x-intercepts