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Ilia_Sergeevich [38]
4 years ago
5

Please help! With explanation, thanks!

Mathematics
1 answer:
Ber [7]4 years ago
4 0
45.6%, I think


If the angle was 45 degrees, then 50% of the circumference of the ice cream would be inside the cone.
But the real angle is 41. 41 = (41/45) * 45

So if we multiply 45 by 41/45, we get 41. In the same way, if multiply the "50%" by 41/45, we get the percentage of ice cream circumference that is in the cone.

50% * 41/45 = 45.6%
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A large consumer goods company ran a television advertisement for one of its soap products.
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Answer:

Step-by-step explanation:

Given that a large consumer goods company ran a television advertisement for one of its soap products.

B = individual purchased the product S = individual recalls seeing the advertisement B∩S = individual purchased the product and recalls seeing the advertisement

The probabilities assigned were P(B)=.20,P(S)=.40, and P(B∩S)=.12

a) P(B/S) = \frac{P(B\bigcap S}{P(S)} \\=\frac{0.12}{0.40} \\=0.30

Yes we can continue the advt since P(B/A) >P(B)

b)

It is preferable to continue advt as chances of purchase after seeing advt is more than purchase without seeing advt.

c) P(B/S) =\frac{P(B\bigcap S}{P(S)} \\=\frac{0.1}{0.3} \\=0.3333

The II advt has the bigger effect since conditional prob is more here.

7 0
4 years ago
Simplify the radical
elena-14-01-66 [18.8K]

Answer:

\sqrt{108}  \sqrt{36  \times 3}  \sqrt{36}  \sqrt{3}   \:  \: 6 \sqrt{3}  \:  \:  \:  \sqrt{108}  = 10.392304845413264

8 0
3 years ago
What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0
Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

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3 years ago
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The answer is f(x)=log(x-5)
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Ervin sells vintage cars. Every three months
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This doesn't make sense ask another
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