Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
It would be mark N? I think
The Prime Factorization of 1050: 2*3*5^2*7<span />
Answer:
The answer is A
Step-by-step explanation:
Down 2 right 3. You can figure this out for other problems like this by choosing any point on the graph and following the slope. It's down because the 2 is negative and 3 is positive to it goes to the right.
Answer:
see explanation
Step-by-step explanation:
∠2 and ∠3 are same- side interior angles and are supplementary.
