Because the angle omega is in QIII, the adjacent side lies to the left of the origin and thus is represented by a negative value. Since sin omega = -3/5, the opposite side is also negative. Use the Pythagorean Theorem to obtain the length of the adjacent side: 5^2 = (-3)^2 + x^2, or 25 = 9 + x^2, or x^2 = 16.
Solving for x: x = plus or minus 4. Since we are in QIII, let x = -4.
Then cos omega is opp / hyp, or -4/5.
Split this polygon into 2 shapes of triangle (top) and rectangle (bottom)
Area of triangle = 1/2 bh = 1/2 (7)(2) = 7
Area of rectangle = wl = 7 x 5 = 35
so
Area of the polygon = Area of triangle + Area of rectangle
= 7 + 35
= 42
Answer
42 square units
Answer: 20 cups of flour
Step-by-step explanation:
Um this is a little hard but i think the answer will about 40. My exact is 37
The answer is log3 k to the seventh power m to the sixth power over n to the ninth power
a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)
7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)
logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)
logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶ / n⁹)
