we are given the reaction Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag. This means for every mole Cu used, there are 2 moles of Ag produced. In this case, given 31.75 g Cu, converting to moles through molar mass and using stoichiometric ratio and the molar mass of Ag, the mass Ag produced is 107.9 grams.
Decomposition and synthesis is the answer
The anaphase includes chromosomes clustered at the poles and a clear area in the center of the cell. remember that the anaphase is the third stage of cell division and in that stage chromosomes <span>move away from one another to opposite poles of the spindle. basically said, sister chromatoids separate during anaphase. </span>
Answer;
Ar (Argon)
Explanation;
-S (Sulfur) atom has 16 electrons, however it forms an anion (negatively charged ion) by gaining two electrons. Therefore; S^2- has 18 electrons. In other words it requires two electrons to form a stable configuration or an octet configuration.
-Argon (Ar) is a noble gas (group 8 element) which means it has an octet configuration. It has 18 electrons similar to an ion of sulfur (S^2-).
Answer:
41.9(w/w) %
Explanation:
Based on the reaction:
Na₂C₂O₄(s) + 2HCl(aq) → H₂C₂O₄(aq) + 2NaCl(aq)
<em>Where 1 mole of sodium oxalate reacts with 2 moles of HCl</em>
Moles of HCl solution to reach end point are:
44.15mL = 0.04415L ₓ (0.250mol / L) = 0.01104 moles of HCl
As 2 moles of HCl reacts per mole of Na₂C₂O₄:
0.01104mol HCl ₓ (1 mol Na₂C₂O₄ / 2 mol HCl) = <em>5.519x10⁻³ moles Na₂C₂O₄</em> are in the sample.
Molar mass of Na₂C₂O₄ is 134g/mol; thus, mass of 5.519x10⁻³ moles Na₂C₂O₄ is:
5.519x10⁻³ moles Na₂C₂O₄ ₓ (134g / mol) = <em>0.740g of Na₂C₂O₄</em> in the sample.
Thus, percent by mass of sodium oxalate in the sample is:
0.740g of Na₂C₂O₄ / 1.766g ₓ 100 =
<h3>41.9(w/w) %</h3>