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kozerog [31]
4 years ago
7

Can someone PLEASE help me with this problem, I’ve tried it multiple times and keep getting it wrong :(

Chemistry
1 answer:
atroni [7]4 years ago
5 0

Answer:

Explanation:

Okay.

From convervation of mass in chemical processes, all the reactants combined have the same mass as all the products.

m react = m prod

m Hg + m O 2 = m HgO + m O 2

114.0g+12.8g=123.1g+ m O 2

Solving for mO2 = 3.70 g

This is what I know.

I do hope I helped you! :)

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A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture co
DaniilM [7]

Answer:

Explanation:

The air 9% mole% methane have an average molecular weight of:

9%×16,04g/mol + 91%×29g/mol = 27,8g/mol

And a flow of 700000g/h÷27,8g/mol = 25180 mol/h

In the reactor where methane solution and air are mixed:

In = Out

Air balance:

91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)

Where X is the flow rate of air in mol/h = <em>20144 mol air/h</em>

<em></em>

The air in the product gas is

95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = <em>289 kg O₂</em>

43058 mol air×29g/mol <em>1249 kg air</em>

Percent of oxygen is: \frac{289kg}{1249 kg} =<em>0,231 kg O₂/ kg air</em>

<em></em>

I hope it helps!

4 0
3 years ago
What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric
Gre4nikov [31]

 The mass of NaCl  formed  is 8.307  grams


<u><em> calculation</em></u>

step 1: write the equation  for reaction

Na₂CO₃  + 2HCl → 2 NaCl  +CO₂ +H₂O

Step 2: find the  moles of Na₂CO₃

moles = mass/molar mass

 The  molar mass of Na₂CO₃  is = (23 x2) + 12 + ( 16 x3) = 106 g/mol

moles  = 7.5 g/106 g/mol =0.071 moles

Step 3: use the  mole ratio to determine the  mole of NaCl

Na₂CO₃:NaCl  is  1:2  therefore the moles of NaCl =0.07  x2 =0.142 moles


Step 4:  calculate mass  of NaCl

mass= moles x molar mass

the molar  mass of NaCl= 23 +35.5 =58.5 g/mol

mass  = 0.142  moles x 58.5 g/mol =8.307  grams

8 0
3 years ago
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Fish need about 5 ppm oxygen dissolved in water to survive. Will water with 5 mg oxygen per
Lelechka [254]

5mg in liter is 5 ppm

Explanation: 1 ppm is one part per million.

1 ppm is 1 mg is one part of million from 1 kg = 1000 000 mg

1 litre water is 1. Kg.

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3 years ago
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Answer:

well what I think is that C is the correct answer

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