Answer : The half life of 28-Mg in hours is, 6.94
Explanation :
First we have to calculate the rate constant.
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = time passed by the sample = 48.0 hr
a = initial amount of the reactant disintegrate = 53500
a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520
Now put all the given values in above equation, we get


Now we have to calculate the half-life.



Therefore, the half life of 28-Mg in hours is, 6.94
Answer:
plzz can you explain in detail this Q
Answer:
a) nitrogen
b) nitrogen =5
Oxygen = 6
Fluorine =7
Explanation:
Usually, if we have two or more elements in a compound, the central atom in the compound is the atom having the least value of electro negativity.
If we consider fluorine, oxygen and nitrogen; nitrogen is the least electronegative of the trio hence it should be the central atom of the triatomic molecule.
The number of valence electrons on the valence shell of each atom is shown below;
nitrogen =5
Oxygen = 6
Fluorine =7
It’s option B 0.0821L.atm/mol.K
The mixture should be
Heterogeneous
Explanation:
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