The concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
- We'll begin by calculating the number of mole in 20.5 g of Zn(C₂H₃O₂)₂
Mass of Zn(C₂H₃O₂)₂ = 20.5 g
Molar mass of Zn(C₂H₃O₂)₂ = 65 + 2[(12×2) + (3×1) + (16×2)]
= 65 + 2[59]
= 183 g/mol
<h3>Mole of Zn(C₂H₃O₂)₂ =? </h3>
Mole = mass / molar mass
Mole of Zn(C₂H₃O₂)₂ = 20.5 / 183
<h3>Mole of Zn(C₂H₃O₂)₂ = 0.112 mole </h3>
- Finally, we shall determine concentration of Zn(C₂H₃O₂). This can be obtained as follow:
Mole of Zn(C₂H₃O₂)₂ = 0.112 mole
Volume = 105 mL = 105 / 1000 = 0.105 L
<h3>Concentration of Zn(C₂H₃O₂)₂ =? </h3>
Concentration = mole / Volume
Concentration of Zn(C₂H₃O₂)₂ = 0.112 / 0.105
<h3>Concentration of Zn(C₂H₃O₂)₂ = 1.067 M</h3>
Therefore, the concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
Learn more: brainly.com/question/25511880
Answer: Groundwater that forms caves because it is slightly acidic.
Explanation:
The water under the ground present inside the cracks and spaces in sand, soil and rocks is called ground water.
When ground water moves through the soil it results in the formation of acid. Further, this acid helps minerals to get dissolve. These minerals get deposited on other places as well.
This process of deposition and erosion helps in the formation of caves.
Thus, it can be concluded that groundwater that forms caves because it is slightly acidic.
Answer:
92.37°C
Explanation:
Assuming the volume remains the same in both the states ( bicycle tire).
Then as per ideal gas equation
where P1, P2 are pressure at two different states and T1, T2 are temperature at these two states
Given:
P1 = 1.34 atm, T1 = 33.0 ° C = 306K
P2 = 1.60 atm, T2 = ?
1.34/306 = 1.60/T_2
⇒ T2 = 1.60×306/1.34
= T2= 365.37K= 92.37°C
Answer:
57.3mL of 0.250M KMnO4 are required
Explanation:
3.225g of oxalic acid are:
3.225g×(1mol / 90.03g) = <em>0.03582mol of oxalic acid</em>
Based on the reaction, 5 moles of oxalic acid react with 2 moles of KMnO4, thus, for a complete reaction of oxalic acid you need:
0.03582mol of oxalic acid × (2mol KMnO4 / 5mol Oxalic Acid) = <em>0.01433mol of KMnO4</em>
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If concentration of KMnO4 is 0.250M, liters in 0.01433mol are:
0.01433mol × (1L /0.250mol) = 0.0573L ≡<em> 57.3mL of 0.250M KMnO4 are required</em>
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I hope it helps!