Answer:
disruptive/diversifying selection
Explanation:
Disruptive (also known as diversifying) selection is a type of natural selection where extreme phenotypic values are more favored rather than intermediate phenotypes. The disruptive selection favors the survivance and reproduction of organisms with extreme phenotypic traits, and in turn impairs the reproduction of organisms with intermediate traits, thereby changing the allele frequencies in the population in order to favor extreme values. An example of disruptive selection is the beak size of Galapagos finches, where extreme phenotypes of this trait have shown to be adaptive according to the type of food found in each island.
You know that mRNA does not have thymine(T) in it. Instead it has uracil(U). So adenine(A) pairs with uracil(U) and cytosine(C) pairs with guanine(G). I hope that helps!
The process of meiosis increases genetic variability as it produces gametes for sexual reproduction.
<span>Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. This process is required to produce egg and sperm cells for sexual reproduction.</span>
P(B) = 1 - P(B') = 1 - (7/12) = 5/12
<span>P(A∩B)=<span><span>P(A∩<span>B′</span>)/</span><span>P(<span>B′</span>) </span></span>× <span><span>P(B)/</span>1
</span></span>Plugging values into the last equation we get:
<span>P(A∩B)=<span><span>1×12×5 / </span><span>6×7×12 </span></span>= <span>542</span></span>
Now we can make use of the following formula
<span>P(A|B)=<span><span>P(A∩B) / </span><span>P(B)</span></span></span><span>
by plugging in the values that we have found.
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<span>5/42 is the numerator and the denominator is 5/12.
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The bottom (denominator) is P(B) which equals 5/12.
<span>P(A|B)=<span><span>5×12 / </span><span>42×5 = 6/210
6/210 = 2/7
</span></span></span><span>p(a[b]) = 2/7</span>
