For this case we have that the generic equation of the line is given by:
Where,
m: slope of the line
b: intersection with the y axis.
Since the line is parallel to PQ, then the slopes are equal.
We have then:
On the other hand we have:
Substituting values we have:
Answer:
The equation of the line that is parallel to line PQ and that has the and intercept b = -3 is:
Answer:
You can put this solution on YOUR website!
the inequality is 500 - 25x >= 200
this insures that he will have at least 200 at the end of the summer.
subtract 200 from both sides of that inequality and add 25x to both sides of that inequality to get 500 - 200 >= 25x
simplify to get 300 >= 25x
divide both sides of that equation by 25 to get 300 / 25 >= x
simplify to get 12 >= x
12 >= x means x <= 12.
when x is smaller than or equal to 12, he will be guaranteed to have at least 200 in the account at the end of the summer.
when x = 12, what is left in the account is 500 - 25 * 12 = 200.
when x = 11, what is left in the account is 500 - 25 * 11 = 225.
when x = 13, what is left in the account is 500 - 25 * 13 = 175.
the maximum number of weeks he can withdraw money from his account is 12.
Step-by-step explanation:
A=Pe^(rt)
P = 800g
t = 8 years
A = 450g
r = This is what we will try and find to start with
450=800e^(r*8)
After running the math through a calculator, we end with r = -0.07192
Now we just re-input this information into our equation: A=800e^(-0.07192*16)
A=800e^(1.15072)
Now we will re-write the equation using the negative exponent rule:
A = 800 1/e^1.15072
Combine right side:
A = 800/e^1.15072
Then do the math:
A = 253.12709836......
That will give us A = 253 (rounded to the whole number)
I hope this helps! :)
Answer:
11
Step-by-step explanation:
140-129=11
The correct answer for this would be the last option. The factors of 48m - 80n are 16(3m - 5n). If you try to solve this, the result would be 48m - 80n. 16 x 3m would be 48m and 16 times 5n would be 80n. Hope this is the answer that you are looking for.
