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Sloan [31]
3 years ago
10

Anna created the poster shown below: A rectangle is shown. The length of the rectangle is labeled as length equal to 36 cm, and

the width is labeled as width equal to 16 cm. What would be the dimensions of the poster at fraction 1 over 4 times its current size?
(answers)
Length = 9 cm, width = 4 cm
Length = 144 cm, width = 64 cm
Length = 32 cm, width = 12 cm
Length = 40 cm, width = 20 cm
Mathematics
2 answers:
Bess [88]3 years ago
7 0

Answer:

she is right i had the test

Step-by-step explanation:


Vitek1552 [10]3 years ago
3 0
The first one because
36 \div 4 = 9
16  \div 4 = 4
I am not sure if this is right but I hope it is!
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17 is the answers to the question

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The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many se
Masja [62]

Answer:

6.64 seconds

Step-by-step explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled, s = 709 feet

Initial velocity of the bucket, u = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

g or 32.1741 ft/sec^{2}

Let the time taken is t seconds.

Formula for distance is given as:

s = ut+\dfrac{1}{2}at^2

Putting all the values:

709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}

6 0
2 years ago
what is the coordinate of the vertex of the parabola y-2=1/12(x+10) a. ( 10,-2) b. (-10,2) c. (-2,10) d. (2.-10)
solniwko [45]

Answer:

y-a= c(x-b)^2

With the vertex V= (b,a)

We see that b = -10 and a = 2 and then the vertes wuld be:

V= (-10,2)

And the best option is:

b. (-10,2)

Step-by-step explanation:

For this problem we have the following function:

y-2 = \frac{1}{2} (x+10)

And if we compare this expression with the general expression for a parabola given by:

y-a= c(x-b)^2

With the vertex V= (b,a)

We see that b = -10 and a = 2 and then the vertes wuld be:

V= (-10,2)

And the best option is:

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4 0
3 years ago
Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.
igomit [66]

Answer:

y=\cot \theta and y=\csc \theta

Step-by-step explanation:

Note that if \cos \theta=1, then \sin \theta=0.

Functions y=\cos \theta,\ \ y=\sin \theta do not have vertical asymptotes at all.

Vertical asymptotes have functions y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.

Functions y=\tan \theta and y=\sec \theta have the same vertical asymptotes (when \cos \theta =0).

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3 0
3 years ago
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devlian [24]

Answer:

i think the anser is 150 sorry if im wrong

Step-by-step explanation:

2x2x2= 8

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5 0
2 years ago
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