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Sloan [31]
3 years ago
10

Anna created the poster shown below: A rectangle is shown. The length of the rectangle is labeled as length equal to 36 cm, and

the width is labeled as width equal to 16 cm. What would be the dimensions of the poster at fraction 1 over 4 times its current size?
(answers)
Length = 9 cm, width = 4 cm
Length = 144 cm, width = 64 cm
Length = 32 cm, width = 12 cm
Length = 40 cm, width = 20 cm
Mathematics
2 answers:
Bess [88]3 years ago
7 0

Answer:

she is right i had the test

Step-by-step explanation:


Vitek1552 [10]3 years ago
3 0
The first one because
36 \div 4 = 9
16  \div 4 = 4
I am not sure if this is right but I hope it is!
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What is the product? Enter your answer as a fraction, in simplified form, in the box. −1/4⋅(−6/11)
ivann1987 [24]

Answer:

3/22

Step-by-step explanation:

-1/4 . (-6/11)

  • You have to multiply the signs: As both are negative, the result will be positive.
  • You have to multiply the numbers in the top part (numerators) and the numbers in the bottom part (denominators)

1 . 6 / 4 . 11 = 6/44

  • Finally, you must simplify the answer by dividing both numbers among the same divisor, in this case the number is 2

6÷2 / 44÷2 = 3/22

4 0
3 years ago
Please Help!!! 10 Points! Brainliest Answer
Crank
The answer is b.) 120 degrees
8 0
3 years ago
Read 2 more answers
Use the graphs to estimate both solutions to x^2+x-4=0
Bogdan [553]

Answer:

No graph so we'll use the quadratic formula

x^2+x-4=0

a = 1

b = 1

c = -4

x = -1 +- sqr root (1^2 - 4 * 1 * -4) / 2

x = (-1 +- sqr root (1 +16) ) / 2

x1 = (-1 + sqr root (17)) / 2

x2 = (-1 - sqr root (17)) / 2

Step-by-step explanation:

4 0
3 years ago
Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Leona [35]
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.

Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:

The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the lowest score of test A is given by 40(21) + 50 = 890

Therefore, the lowest score of test A is 890.



Part B:

The mean score is a measure of location, so both addition and multiplying the mean score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the mean score of test A is given by 40(29) + 50 = 1,210

Therefore, the mean score of test A is 890.



Part C:

The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50 to the result will not affect the standard deviation of test A.

Thus, the standard deviation of test A is given by 40(2) = 80

Therefore, the standard deviation of test A is 80.



Part D

The Q3 score is a measure of location, so both addition and multiplying the Q3 score of test B by 40 and adding 50 to the result will affect the Q3 score of test A.

Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170

Therefore, the Q3 score of test a is 1,170.



Part E:

The median score is a measure of location, so both addition and multiplying the median score of test B by 40 and adding 50 to the result will affect the median score of test A.

Thus, the median score of test A is given by 40(26) + 50 = 1,090

Therefore, the median score of test A is 1,090.



Part F:

The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50 to the result will not affect the IQR of test A.

Thus, the IQR of test A is given by 40(6) = 240

Therefore, the IQR of test A is 240.
6 0
3 years ago
At shop A, 2 pounds of crawfish costs $6. At shop B, 5 pounds of crawfish costs $15. Jacob says the cost per pound is the same a
Tasya [4]
Yes, they are both $3
4 0
3 years ago
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