Hello!
To find the area of a rectangular prism you do 2(lw + lh + wh)
Put in the values
2(9 * 2 + 9 * 6 + 2 * 6)
2(18 + 54 + 12)
2(84)
2 * 84 = 168
The answer is 168 cubic inches
Hope this helps!
The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
<h3>What is the value of sin (π/2)?</h3>
The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.
Suppose the value of this function is <em>x</em>. Thus,
Solve it further,
......1
The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,
Put this value in the equation 1,
Thus, the range will be,
Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
Learn more about the sine values here;
brainly.com/question/10711389
Answer:
D, 20:30
Step-by-step explanation:
At first glance, this does not seem like the correct ratio. But I'll spare you a long intro and get into it:
20:30: Divide both of them by 10
=2:3
2 x 12:3 x 12
24:36
Hope this helps!
Answer:
36 units^2
Step-by-step explanation:
The area of a triangle is 1/2*base*height. Knowing this is just 2 triangles means you solve for 1 triangle, then multiply that by 2
Answer:
100
Step-by-step explanation:
Mixed candy question... Skittles jar... to be filled with Jelly beans.
Let's first calculate the volume of the jar. We'll assume it's a regular cylindrical prism jar, unlike the one on the photo which is narrower on top.
V = π * r² * h = π * (3.5)² * 11.5 = 140.875 π = 442.6 cubic cm
Now, we don't have the precise measurement of a jelly bean, but we know it's roughly 2-3 cubic cm. The precision isn't needed to answer this question, just to have a rough idea... it's no 300 cu cm per jelly bean.
So, let's assume a 3 cu cm per jelly bean (2 cu cm wouldn't the final answer)....
442.6 / 3 = 147.5 jelly beans, approximately.
So, can they fit 100,000? No
Can we fit 10,000 in there? No
Can we fit 100? Yes.
Can we fit 1? Certainly
The most reasonable lower-limit would then be 100.
