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fomenos
2 years ago
7

What is the total surface area?

Mathematics
1 answer:
Anastasy [175]2 years ago
3 0

Answer:

2198 cm²

Step-by-step explanation:

Total surface area of a cylinder = 2πrh + 2πr²

Radius, r = diameter/2

= 20cm/2

= 10 cm

Height, h = 25 cm

Total surface area of a cylinder = 2πrh + 2πr²

= 2*3.14*10*25 + 2*3.14*10²

= 1,570 + 6.28*100

= 1,570 + 628

= 2198 cm²

Total surface area of a cylinder = 2,198 cm²

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Sveta_85 [38]

In the given image, a_{23} is 5. The correct option is the first option 5

<h3>Matrix notation</h3>

From the question, we are to determine which entry in the given matrix represents a_{23}

NOTE: For any entry denoted as a_{mn}, it represents the entry in the <em>m</em>-th row and <em>n</em>-th column.

Thus,  

 a_{23} represents the entry in the 2nd row and 3rd column.

In the given image, the entry in the 2nd row and 3rd column is 5.

Hence, in the given image, a_{23} is 5. The correct option is the first option 5

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1 year ago
The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly sel
garri49 [273]

Complete question:

The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly selects 45 customers and records the amount of time from the moment they stand in the back of a line until the moment the cashier scans their first item. He calculates the mean and standard deviation of this sample to be barx = 4.2 minutes and s = 2.0 minutes. If appropriate, find a 90% confidence interval for the true mean time (in minutes) that customers at this supermarket wait in a check-out line

Answer:

(3.699, 4.701)

Step-by-step explanation:

Given:

Sample size, n = 45

Sample mean, x' = 4.2

Standard deviation \sigma = 2.0

Required:

Find a 90% CI for true mean time

First find standard error using the formula:

S.E = \frac{\sigma}{\sqrt{n}}

= \frac{2}{\sqrt{45}}

= \frac{2}{6.7082}

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Standard error = 0.298

Degrees of freedom, df = n - 1 = 45 - 1 = 44

To find t at 90% CI,df = 44:

Level of Significance α= 100% - 90% = 10% = 0.10

t_\alpha_/_2_, _d_f = t_0_._0_5_, _d_f_=_4_4 = 1.6802

Find margin of error using the formula:

M.E = S.E * t

M.E = 0.298 * 1.6802

M.E = 0.500938 ≈ 0.5009

Margin of error = 0.5009

Thus, 90% CI = sample mean ± Margin of error

Lower limit = 4.2 - 0.5009 = 3.699

Upper limit = 4.2 + 0.5009 = 4.7009 ≈ 4.701

Confidence Interval = (3.699, 4.701)

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Answer:

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Answer:

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