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marishachu [46]
2 years ago
15

How can x minus two-thirds = StartFraction 5 over 6 EndFraction be solved for x in one step?

Mathematics
1 answer:
Brums [2.3K]2 years ago
5 0

Add Two-thirds to both sides

solution:

x-2/3= 5/6

We have to find how this can be solved for "x" in one step

Remember that,

We we add or subtract same number from both sides of a equation, the equation still remains true

Therefore, from given,

x-2/3=5/6

Add Two-thirds to both sides

x-2/3+2/3=5/6+2/3

x=5/6+2/3

x=9/6

Add Two-thirds to both sides to solve the sum

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How to get answer for number 2: | 5-i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}

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\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3

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