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Answer:
For The value of a = 0 and c = 0 , The given expression equality is true
Step-by-step explanation:
Given expression as :
= a - 2
Or, 3 a² + ac + 2 c - 6 a = ( a - 2 ) × ( 3 a - c )
Or, 3 a² + ac + 2 c - 6 a = 3 a² - ac - 6 a + 2 c
Or, ( 3 a² + ac + 2 c - 6 a ) - ( 3 a² - ac - 6 a + 2 c ) =0
Or, ( 3 a² - 3 a² ) + ( ac + ac ) + ( 2 c - 2 c ) + ( - 6 a + 6 a ) = 0
or, 0 + 2 ac + 0
Or, 2 ac = 0
∴ a =0 and c = 0
Hence For The value of a = 0 and c = 0 , The given expression equality is true . Answer
In order to add fractions you need to change the denominators to make sure they are the same. Then, all you have to do is add the two numerators like normal and keep the denominator the same.
Hope this helps!!!! :D
Answer:
(3,2)
Step-by-step explanation:
Let's solve this via elimination method:

By subtracting equation 2 from equation one we obtain:

Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1. Let y=2 and so:

Therefore the solution for the system of equations is:
x=3 and y = 2 as an ordered pair we have (3,2)
I hope this helps you
✔cos^2A+sin^2A=1
✔1-cos^2A=sin^2A
✔cos2A=cos^2A-sin^2A
✔sin2A=2.sinA.cosA
secA=1/cosA
tgA=sinA/cosA
sin^2A/1/cos^2A-sin^2A/cos^2A
sin^2A.cos^2A/cos2A
2.sin^2A.cos^2A/cos2A
sin2A.2.sin2A/cos2A
tg2A.2.sin2A