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andreyandreev [35.5K]
3 years ago
8

Which ratios are equal to cos(B)? Choose the TWO ratios that apply.

Mathematics
1 answer:
mestny [16]3 years ago
5 0

Answer:2 and 5

Step-by-step explanation:

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A line passes through (9, –9) and (10, –5).Write an equation for the line in point-slope form.
Ket [755]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-(-9)}{10-9}\implies \cfrac{-5+9}{1}\implies \cfrac{4}{1}\implies 4

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-9)=4(x-9)\implies\underline{y+9=4(x-9)} \\\\\\ y+9=4x-36\implies y=4x-45\implies \stackrel{standard~form}{\underline{-4x+y=-45}}

quick note:

the "x" must not have a negative coefficient for the standard form, though in this case it shows like so in the inappropriate choices above.

5 0
3 years ago
Solve 15 – x = 2 a. –13 b. 17 c. 13 d. 3
anyanavicka [17]
The answer should be c. 13
3 0
3 years ago
When this 3 digit number is rounded to the nearest hundred it rounds to 900.The digit in the ones place is the fifth odd number
gizmo_the_mogwai [7]

Answer:

949

Step-by-step explanation:

If the 3 digit number is rounded to 900, then this number is between 900 and 950.

The digit in the ones place is the fifth odd number begginning with 1, so this number is number 9.

Lastly, the sum of digits is 22.

Putting our number as 9x9, where x is the tens digit, we know that 9 + x + 9 = 22, so we have that x = 4

So, our number is 949

3 0
4 years ago
A. What are the coordinates of the vertices of the triangle below?
Viktor [21]

Answer:

Solution given:

<u>A.coordinate are</u>

A(-2,3)

B(0,-3)

C(4,5)

<u>B</u><u>.</u><u>Each</u><u> </u><u>length</u><u> </u><u>are</u><u> </u><u>:</u>

we have

length \sqrt{(x2-x1)²+(y2-y1)²}

now

AB:\sqrt{(-2-0)²+(3+3)²}=2\sqrt{10}units

BC:\sqrt{(0-4)²+(-3-5)²}=4\sqrt{5}units

AC:\sqrt{(-2-4)²+(3-5)²}=2\sqrt{10}units

<u>C.</u><u> the </u><u>figure</u><u>:</u>

<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>

base[b]=AB=perpendicular [p]=AC

hypotenuse [h]=BC

we have

h²=p²+b²

substituting value

(4\sqrt{5})²=2p²

16*5=2*(2\sqrt{10})²

80=2*4*10

80=80

<u>SO</u><u> </u><u>IT</u><u> </u><u>IS</u><u> </u><u>RIGHT</u><u> </u><u>ANGLED</u><u> </u><u>ISOSCELES</u><u> </u><u>TRIANGLE</u><u>.</u>

4 0
3 years ago
When a jug is half-filled with marbles, it weighs 2.6 kg. If the jug weighs 4 kg when full, find the weight of the empty jug.
Soloha48 [4]

Let x be the jug, \frac{1}{2} for half-filled, y for the weight of the jug when empty.

∵ \frac{1}{2}x + y = 2.6 kg

∵ x = 4 kg

∴ \frac{1}{2} ⋅ 4 + y = 2.6 kg

∴ 2 + y =2.6 kg

∵ y = 2.6 - 2 = 0.6 kg

∴ The weight of the empty jug = 0.6 kg


8 0
3 years ago
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