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Ierofanga [76]
3 years ago
7

Identify the pair of supplementary angles.

Mathematics
1 answer:
777dan777 [17]3 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

We know that, the sum of measures of supplementary angles is 180°

So, the Correct choice is :

  • 65° and 115°

because, 65° + 115° = 180°

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Question 7
netineya [11]

Answer:

135 cubic centimeters

Step-by-step explanation:

The formula for volume of a pyramid is lwh/3 = V.

The base (length and width, remember) is 9 cm * 9 cm, because it's a square pyramid. The height is 5 cm. Plug these in!

lwh/3 = V

9*9*5/3 = V

<u>V = 135 cubic centimeters</u>

5 0
4 years ago
Suppose an arrow is shot upward on the moon with a velocity of 44 m/s, then its height in meters after tt seconds is given by h(
andreev551 [17]

Answer:

a. 38.19m/s

b. 38.605m/s

c. 38.937m/s

d. 39.0117m/s

e. 39.01917m/s

Step-by-step explanation:

The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:

v_a_v_g = \frac{\Delta x}{\Delta t} =\frac{x_f-x_i}{t_f-t_i}

Where:

x_f=Final\hspace{3}distance\hspace{3}traveled\\x_i=Initial\hspace{3}distance\hspace{3}traveled\\t_f=Final\hspace{3}time\hspace{3}interval\\t_i=Initial\hspace{3}time\hspace{3}interval

a. Let's find h(3) and h(4) using the data provided by the problem:

h(3)=44(3)-0.83(3^2)=124.53=x_i\\h(4)=44(4)-0.83(4^2)=162.72=x_f

The average velocity over the interval [3, 4] is :

v_a_v_g=\frac{162.72-124.53}{4-3} =38.19m/s

b. Let's find h(3.5) using the data provided by the problem:

h(3.5)=44(3.5)-0.83(3.5^2)=143.8325=x_f

The average velocity over the interval [3, 3.5] is :

v_a_v_g=\frac{143.8325-124.53}{3.5-3} =38.605m/s

c. Let's find h(3.1) using the data provided by the problem:

h(3.1)=44(3.1)-0.83(3.1^2)=128.4237=x_f

The average velocity over the interval [3, 3.1] is :

v_a_v_g=\frac{128.4237-124.53}{3.1-3} =38.937m/s

d. Let's find h(3.01) using the data provided by the problem:

h(3.1)=44(3.01)-0.83(3.01^2)=124.920117=x_f

The average velocity over the interval [3, 3.01] is :

v_a_v_g=\frac{124.920117-124.53}{3.01-3} =39.0117m/s

e. Let's find h(3.001) using the data provided by the problem:

h(3.001)=44(3.001)-0.83(3.001^2)=124.5690192=x_f

v_a_v_g=\frac{124.5690192-124.53}{3.001-3} =39.01917m/s

7 0
3 years ago
Find the domain for the function f(x)=sqrt x^2-x+6
dybincka [34]

Answer:

The domain is {x : x ∈ R} or (-∞ , ∞)

Step-by-step explanation:

* Lets explain how to find the domain

- The domain of the function is the values of x which make the

  function defined

- The quantity under the square root must be ≥ 0 because there is

  no square root for negative value

* Lets solve the problem

∵ f(x) = √(x² - x + 6)

∴ The value of (x² - x + 6) must be greater than or equal zero because  

   there is no square root for negative value

- Graph the function to know which values of x make the quantity

  under the root is negative that means the values of x which make

  the graph under the x-axis

∵ The graph doesn't intersect the x-axis at any point

∵ All the graph is above the x-axis

∴ There is no value of x make f(x) < 0

∴ x can be any real number

∴ The domain of f(x) is all real numbers

∴ The domain is {x : x ∈ R} or (-∞ , ∞)

6 0
4 years ago
Rachel and Keegan are building a stand like the one shown to display framed photos. what is the surface area of the stand? lengt
raketka [301]

Answer:

it a because digkjg

Step-by-step explanation:

1 goes to 2 adnd it stops like that

4 0
3 years ago
Helpppppppppppppppppppppppppp
AfilCa [17]

Answer:

3/4 I believe...............

4 0
3 years ago
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