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nasty-shy [4]
3 years ago
9

Find the rule and the graph of the function whose graph can be obtained by performing the translation 4 units right and 3

Mathematics
2 answers:
Feliz [49]3 years ago
5 0

Answer:

oh dayung neyece

Step-by-step explanation:

noh eye wownt because garebahge

sammy [17]3 years ago
5 0

Answer:

no tienes idea de lo que estoy diciendo, chico

Step-by-step explanation:

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What points are solutions for the system of equations?
siniylev [52]
If it's written correctly, I believe the points are (5 , 140) and (20 , 520). First equation indicates a parabola and the second a line. The parabola crosses the line at two points.
3 0
3 years ago
The cubic crystal company has a new crystal cube they want to sell. The packaging manager insists that the cubes be arranged to
Nat2105 [25]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

height  \ \ \ \ \ \ \ Width    \ \ \ \ \ \ \ Length\\\\

   1 \ \ \ \ \ \ \  \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \  \ \ \ \ \ \ \  12\\\\ 1   \ \ \ \ \ \ \ \ \ \ \ \ \ \  2 \ \ \ \ \ \ \  \ \ \ \ \ \ \  6\\\\ 1  \ \ \ \ \ \ \ \ \ \ \ \ \ \  3  \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4\\\\2  \ \ \ \ \ \ \ \ \ \ \ \ \ \  2   \ \ \ \ \ \ \ \ \ \ \ \ \ \  3\\\\

7 0
2 years ago
Read 2 more answers
The length of a rectangle is 71/2 inches and the width is 23/4 inches. What is the ratio, using whole numbers, of the length to
Over [174]

Answer:

142:23

Step-by-step explanation:

The length of the rectangle is given as 71/2 while its width is 23/4

We are required to determine the ratio of the length to the width;

length:width

(71/2):(23/4)

(71/2)/(23/4)

71/2 * 4/23 = 142/23

The ratio of the length to the width is thus;

142:23

6 0
2 years ago
I BET YOU CANT SOLVE THIS...
e-lub [12.9K]
The answer is 61 7/20
8 0
3 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
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