Let a and b be integers and b>a, then we can say:
(b-a)/3=5 now multiply both sides by 3
b-a=15
b=15+a
So there are infinitely many pairs of integers that satisfy the conditions given in the problem. For any value a, b will be 15 units greater.
Answer:
1in x 2 + 1 in =3in
2 times 1 is 2 + 1 equals 3
Answer:
11.89
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
25/6 = 4.166666666667
sine it is the 6 that is repetitive, we place the bar on the 6 only
