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9966 [12]
3 years ago
13

Solve x/10 = –7. A. x = –0.7 B. x= –17 C. x = –70 D. x = 3

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0
The answer would be c because wou would have to take 10 and multiply it with -7
konstantin123 [22]3 years ago
4 0
\frac{x}{10} = -7   Multiply both sides by 10
x = -70

C. x = -70
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podryga [215]

Answer:45



Step-by-step explanation:


6 0
3 years ago
Chen writes down a two digit number. He finds out that if he swapped the numbers, it would be three more than the 1/3 of the ori
inna [77]

Answer:

Step-by-step explanation:

From the information given,

Let the two digits that Chen writes down to be p and q

where,

q will be in the unit place and p will be in the tens place.

So, the value of the digit = 10p + q

So, if he swapped the number, he will have 10q + p

However,

the new number determined is thrice more than the 1/3 pf the original number.

i.e

the 1/3rd of the original number = \dfrac{1}{3}(10p+q)

=\dfrac{10p+q}{3}

thrice more than that will be = \dfrac{10p+q}{3} + 3

∴

\dfrac{10p+q}{3} + 3 = 10q+p

multiply through by 3, we have :

10p+q + 9 = 30q + 3p

collecting the like terms, we have:

10p - 3p +q -30q +9 = 0

7p - 29q +9 = 0

7p - 29q = -9

Therefore, p,q lie between 0 and 9

Therefore, the possibility of the original number is p = 7 and q = 2

8 0
3 years ago
Write an equation for the function graphed below. k(t)=
zloy xaker [14]

Answer:

I think that the equation would be Y= -2X^2-4X-4 .

Step-by-step explanation:

Hope it wad helpful :)

5 0
2 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
I need help plz plz plz
Katena32 [7]
Your answer to this question is B
3 0
3 years ago
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