The members of a possible set C are {6, 9, 12}
<h3>Set theory</h3>
The universal set is the set that contains all other sets. Given the following sets
ξ = {x:x is an integer, 2 ≤ x ≤ 14}
B = {x:x is a prime number}
A = {x:x is a multiple of 3}
The sets B and A are:
B = {2, 3, 5, 7, 11}
A = {3, 6, 9, 12}
If C is a subset of A with a cardinality of 3, hence the required set will be {6, 9, 12}. Note that 3 is excluded since B n C must be an empty set.
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Answer:
Step-by-step explanation:
count the + and - signs that usually tells you the amount of terms
d is the answer.
Answer:
non-linear
Step-by-step explanation:
Hi !! your answer is : 14y-5 !!
Answer:
120
Step-by-step explanation:
Here, we want to get the possible value of A
Now, we should understand that the value of an angle in triangle cannot be more than 180
Also, cosine can only be negative in the second and the 3rd quadrant
So,
arc cos (-0.5) = 120 , 300 , 60
But 60 is not correct as it will give a negative value
300 is not correct also as it is more than the angles present in a triangle
Thus, our answer is 120