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faust18 [17]
3 years ago
14

Charlene is a video game designer and wants to make sure that her games can be played on all types of screens. In order for the

games to work on both devices with a standard aspect ratio and those with widescreen aspect ratios, the playable area of the games should have an aspect ratio of 3:2. This means that the width is equal to times the height. On one type of tablet, the playable area of the game on the screen is 54 square inches. Write and solve a system of equations to determine the dimensions of the playable area. A. The playable area has a width of 13.5 inches and a height of 9 inches. B. The playable area has a width of 6 inches and a height of 9 inches. C. The playable area has a width of 6 inches and a height of 4 inches. D. The playable area has a width of 9 inches and a height of 6 inches.
Mathematics
2 answers:
Nikitich [7]3 years ago
4 0

Answer:

The playable area has a width of 9 inches and a height of 6 inches.

Step-by-step explanation:

There are a number of ways you can get there.

1. Check the answers to see which have the right area and aspect ratio.

A: area = 24 in² — does not match 54 in²

B: area = 54 in², aspect ratio 6:9 = 2:3 — does not match 3:2 aspect ratio

C: area = 54 in², aspect ratio 9:6 = 3:2 — matches problem statement

D: area = 121.5 in² — does not match 54 in²

2. If the screen were 3:2 (inches), its area would be 6 in². The area of 54 in² is 9 times that value, so the actual screen dimensions are √9 = 3 times 3:2. That is, they are width:height = 9:6 inches — matches selection C.

3. You can write equations for width and height and solve.

w/h = 3/2

wh = 54

Substituting w=3/2·h into the second equation gives

... (3/2)h·h = 54

... h² = 36 . . . . . multiply by 2/3

... h = √36 = 6 . . . . square root, result in inches

Zielflug [23.3K]3 years ago
3 0

Answer:

D. The playable area has a width of 9 inches and a height of 6 inches.

Step-by-step explanation:

if the playable area is 54 and that such ratio of dimensions is 3:2

Then we are basically being asked to find the factor of ratios below that also multiply to get 54

54 = 9 x 6 and this is also a ratio of 3:2

As 3(3 + 2) = 54

and as width was asked first when ratio was given 3:2

The width therefore is 9 and the height is 6

So answer is D

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s344n2d4d5 [400]

First, change each mixed fraction into improper

2 3/8 = 19/8

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The problem will look like: (19/8)/(7/4)

To solve, flip the second fraction, and change the division sign into a multiplication sign.

(19/8)/(7/4) = (19/8) x (4/7)

Multiply across

(19/8) x (4/7) = 76/56

Simplify.

76/56 simplified = 19/14

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hope this helps

7 0
4 years ago
(09.02 HC)
Vesna [10]
We factor the equation to get:

-(x-25)^2+361

In the form a(x-h)^2+k, the vertex is (h, k), so the vertex is (25, 361).  This means that the studio makes the most profit from selling 25 memberships, and thus makes 361 dollars.

B.  The x-intercepts are the values of x for which f(x) is 0.  This equation can be factored as (-a+6)(a-44)=0, with solutions 6 and 44.  Therefore, by selling either 6 memberships or 44 memberships, the studio breaks even, neither making nor losing money.
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3 years ago
36(pi) cubed divides by (pi) 3 squared
AleksAgata [21]
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3 years ago
Select the correct answer.
Kaylis [27]

For this case we have that by definition, the volume of a rectangular prism is given by:

V = A_ {b} * h

Where:

A_ {b}:It is the area of the base of the prism

h: It is the height

A_ {b} = w * l

Where:

w: is the width

l: is the length

According to the data of the statement we have:

w = 16 \ in\\l = 4h\\V = 4,096 \ in ^ 3

Substituting the data we have:

A_ {b} = 16 * 4h = 64h\\64h * h = 4,096\\64h ^ 2 = 4,096\\h ^ 2 = \frac {4096} {64}\\h ^ 2 = 64\\h = \pm \sqrt {64}\\

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So the height is8 \ in

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8 \ in

6 0
3 years ago
Find all solutions of each equation on the interval 0 ≤ x < 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
3 years ago
Read 2 more answers
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