Question

Write an equation of the circle with center (6, 2) and radius 4.

Answer 1

Answer:

$(x-6)^2+(y-2)^2=16$.

Step-by-step explanation:

$(x-h)^2+(y-k)^2=r^2$ is the equation for a circle with center (h,k) and radius r.

You are given center (6,2) and radius 4.

So we will replace h with 6 and k with 2 and r with 4.

This gives us:

$(x-6)^2+(y-2)^2=4^2$

Simplify:

$(x-6)^2+(y-2)^2=16$.

Answer 2

For this case we have that by definition, the equation of a circle is given by:

$(x-h) ^ 2 + (y-k) ^ 2 = r ^ 2$

Where:

$(h, k):$It is the center of the circle

r: It is the radius of the circle

According to the data we have to:

$(h, k) :( 6.2)\\r = 4$

Substituting:

$(x-6) ^ 2 + (y-2) ^ 2 = 4 ^ 2\\(x-6) ^ 2 + (y-2) ^ 2 = 16$

ANswer:

$(x-6) ^ 2 + (y-2) ^ 2 = 16$