We have been given for a normal distribution the mean time it takes to walk to the bus stop is 8 minutes with a standard deviation of 2 minutes. And the mean time it takes for the bus to get to school is 20 minutes with a standard deviation of 4 minutes.
(a) Average time that it would take reach school can be obtained by adding the average times.
8+20 = 28 minutes.
(b) Standard deviation of the trip to school can be found as:

Therefore, standard deviation of the entire trip is 4.47 minutes.
(c) Let us first find z score corresponding to 30 minutes.
We need to find the probability such that 
Therefore, the required probability is 0.67.
(d) If average time to walk to school is 10 minutes, then overall average time for the trip will be 10+20 = 30 minutes.
(e) Standard deviation won't change it will remain 4.47
(f) The new probability will be:


Therefore, probability will be 0.50.
Let M = amount of money in ATM at the beginning
M - 18(100) = M - 1800
The change is a decrease of $1,800
Answer:
Step-by-step explanation:
the current ages:
father= 32 yrs old
son=5 yrs old
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4(5+x) = 32+x
20+4x = 32+x
4x-x = 32–20
3x =12
x = 12/3
x = 4 years
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after the 4 years later the farther age will be 36 ( 32+4 = 36)
the son will be 9 ( 5+4= 9 years)
the x presents how the father will be after 4 times the age of the son
6: -8+4V
8: -9-15V OR -9+(-)15V
10:-17+33V