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lisabon 2012 [21]
3 years ago
5

9. Write the slope-intercept form of the equation of the line through the given points. Write answer as y=mx+b. through: (-4, 5)

and (1, 0) Your answer​
Mathematics
2 answers:
Brrunno [24]3 years ago
5 0

Answer:

which is the slope-, intercept equation of the line with a slope of -2 and a y-intercept of ,5?

densk [106]3 years ago
3 0

Answer:

y = -x + 1

Step-by-step explanation:

(-4,5) (1,0)

Find distance through a number line.

Distance(Slope):

(5,-5)

Slope form:

y/x, Apply:

-5/5

Reduce:

-1/1 or -1

To find the y-intercept get x to be at zero and see where y ends. Let's use the point (1,0):

(1,0) use slope -1x to get x to zero:

= (0,1)

y-intercept: (0,1)

Now write in slope-intercept form:

y = mx + b

so,

y = -1x + 1 or y = -x + 1 or y = -1/1x + 1

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X
AURORKA [14]

Answer:

\theta \approx 1.23^\circ

Step-by-step explanation:

The expression has been given as:

tan(\theta) = \frac{50}{18}

Required: Find \theta

Simplify the fraction

tan(\theta) = 2.7778

Take arc tan of both sides

\theta = tan^{-1}(2.7778)

\theta \approx 1.23^\circ

8 0
3 years ago
How much wrapping paper is needed to cover the gift box shown below?<br> SA = 2Lw + 2Lh + 2wh
Brrunno [24]

Answer:

528 square inches

Step-by-step explanation:

SA = 2(10·16) + 2(10·4) +2(4·16)

= 2(160)+2(40)+2(64)

= 320 + 80 + 128

= 528 square inches

8 0
3 years ago
Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
3 years ago
118 {121÷(11×11)-(-4)-(3-7)}​
Rama09 [41]

<u>Q</u><u>uest</u><u>ion</u><u>:</u>

To Simplify:

118 {121÷(11×11)-(-4)-(3-7)}

<u>Solu</u><u>tion</u>:

↠118 {121÷121+4-(-4)}

↠118 {1+4+4}

↠118 {5+4}

↠118{9}

↠118×9

↠1062

▬▬▬▬▬▬▬▬▬▬▬▬

The upper Solution is done by applying BODMAS

<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>

B→ Bracket

O→ Of

D→ Division

M→ Multiplication

A→ Addition

S→ Subtraction

5 0
3 years ago
Read 2 more answers
What is the rule
Taya2010 [7]
Add 5

y is found by adding 5 to x
5 0
3 years ago
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