We have that for the Question it can be said that the NaOH combines with CH_3COOH to produce CH_3COONa (Salt)
From the question we are told
how should the ph of a 0.1 m solution of <em>nac2h3o2</em> compare with that of a 0.1 m <u>solution </u>of kc2h3o2?
Generally
with the ph of a 0.1 m solution of <em>nac2h3o2</em> compared with that of a 0.1 m <u>solution </u>of kc2h3o2 ,we see that the salt produce is a weak acid and strong akali salt
We see that the salt produced in water gives a base from the derived weak acid
The salt produce is CH_3COONa
Therefore
the NaOH combines with CH_3COOH to produce CH_3COONa (Salt)
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Absolutely false. in fact exact opposites. A compound is made up of multiple elements.
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<h3><u>Answer;</u></h3>
EtO-PHE-NH2 + H+ _______ EtO-PHE-NH3+ Cl-
<h3><u>Explanation;</u></h3>
- <em><u>p-phenetidine is p-ethoxy aniline so the amino group acts as a base. The free electron pair on nitrogen will form a coordinate covalent bond with the H+ from the ionized HCl. </u></em>
- HCl is used for the acid-base reaction in p-phenetidine in amide synthesis of acetophenetidin rather than water becuase HCl's polarity contributes to a reaction driven to the right. It protonates the amine group, making it easy to dissolve.
